Python OpenCV寻找两条曲线直接的最短距离
作者：迎迎一笑
这篇文章主要为大家详细介绍了Python OpenCV寻找两条曲线直接的最短距离，文中示例代码介绍的非常详细，具有一定的参考价值，感兴趣的小伙伴们可以参考一下
本文实例为大家分享了Python OpenCV两条曲线直接最短距离的寻找方法，供大家参考，具体内容如下
import numpy as np
import math
import cv2
def cal_pt_distance(pt1, pt2):
dist = math.sqrt(pow(pt1[0]-pt2[0],2) + pow(pt1[1]-pt2[1],2))
return dist
font = cv2.FONT_HERSHEY_SIMPLEX
img = cv2.imread('01.png')
#cv2.imshow('src',img)
gray = cv2.cvtColor(img,cv2.COLOR_BGR2GRAY)
gray = cv2.GaussianBlur(gray, (3,3), 0)
ret,thresh = cv2.threshold(gray, 150, 255, cv2.THRESH_BINARY)
image,contours,hierarchy = cv2.findContours(thresh, cv2.RETR_EXTERNAL, cv2.CHAIN_APPROX_NONE)
#thresh,contours,hierarchy = cv2.findContours(thresh, cv2.RETR_LIST, cv2.CHAIN_APPROX_NONE)
flag = False
minDist = 10000
minPt0 = (0,0)
minPt1 = (0,0)
for i in range(0,len(contours[1])):#遍历所有轮廓
pt = tuple(contours[1][i][0])
#print(pt)
min_dis = 10000
min_pt = (0,0)
#distance = cv2.pointPolygonTest(contours[1], pt, False)
for j in range(0,len(contours[0])):
pt2 = tuple(contours[0][j][0])
distance = cal_pt_distance(pt, pt2)
#print(distance)
if distance < min_dis:
min_dis = distance
min_pt = pt2
min_point = pt
if min_dis < minDist:
minDist = min_dis
minPt0 = min_point
minPt1 = min_pt
temp = img.copy()
cv2.drawContours(img,contours,1,(255,255,0),1)
cv2.line(temp,pt,min_pt,(0,255,0),2,cv2.LINE_AA)
cv2.circle(temp, pt,5,(255,0,255),-1, cv2.LINE_AA)
cv2.circle(temp, min_pt,5,(0,255,255),-1, cv2.LINE_AA)
cv2.imshow("img",temp)
if cv2.waitKey(1)&0xFF ==27: #按下Esc键退出
flag = True
break
if flag:
break
cv2.line(img,minPt0,minPt1,(0,255,0),2,cv2.LINE_AA)
cv2.circle(img, minPt0,3,(255,0,255),-1, cv2.LINE_AA)
cv2.circle(img, minPt1,3,(0,255,255),-1, cv2.LINE_AA)
cv2.putText(img,("min_dist=%0.2f"%minDist), (minPt1[0],minPt1[1]+15), font, 0.7, (0,255,0), 2)
cv2.imshow('result', img)
cv2.imwrite('result.png',img)
cv2.waitKey(0)
cv2.destroyAllWindows()原图：
结果图：
以上就是本文的全部内容，希望对大家的学习有所帮助，也希望大家多多支持脚本之家。