python爬虫字体加密的解决
作者：L'y
本文主要介绍了python爬虫字体加密的解决，文中通过示例代码介绍的非常详细，对大家的学习或者工作具有一定的参考学习价值，需要的朋友们下面随着小编来一起学习学习吧
直接点 某8网 https://*****.b*b.h*****y*8*.com/
具体网址格式就是这样的但是为了安全起见,我就这样打码了.
抛出问题
我们看到这个号码是在页面上正常显示的
F12 又是这样就比较麻烦,不能直接获取.
用requests库也是获取不到正常想要的 源码的,因为字体加密了.
查看页面源代码又是这样的.所以就是我们想怎么解密呢.
解决步骤
- 获取到真正的源码
- 找到对应的字体库
- 进行解析操作.
获取到真正的源码
为什么用webdriver,因为
requests拿不到真正的源码.
from selenium import webdriver
# --- 进行chrome的配置
options = webdriver.ChromeOptions()
prefs = {"profile.managed_default_content_settings.images": 2} # 设置无图模式
options.add_experimental_option("prefs", prefs)
options.add_argument("service_args = ['–ignore-ssl-errors = true', '–ssl-protocol = TLSv1']")
options.binary_location = r'C:\Program Files\Google\Chrome\Application\chrome.exe'
# ---- chrome进行端口接管调用
options.add_argument('-incognito')
driver = webdriver.Chrome(options=options)
driver.set_page_load_timeout(5)
# --- 设置宽和高位置
driver.maximize_window()
# --- 拦截webdriver检测代码
driver.execute_cdp_cmd("Page.addScriptToEvaluateOnNewDocument",
{"source": """
Object.defineProperty(navigator, 'webdriver', {
get: () => undefined
})
"""})
找到对应的字体库
这上面进行申明了告诉了我们这个是字体
base64,然后就是那下来然后生成文件.
# 示例
import base64
# 省略了很长的...
b64_code = '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'
with open('font.ttf', 'wb') as f:
f.write(base64.decodebytes(b64_code.encode()))
from fontTools.ttLib import TTFont # 导包
font = TTFont('font.ttf')
font.saveXML('font.xml')
# 简单封装下
import base64
def w_tff(one_html):
res_tff = re.findall(r';base64,(.*?)"', one_html, re.S)
if res_tff and len(res_tff) == 1:
new_res_ttf = res_tff[0]
with open('123_new_ttf.ttf', 'wb') as f:
f.write(base64.decodebytes(new_res_ttf.encode()))
读取文件找到里面的对应关系,就是 你这个数字的格式 是存储在.ttf文件里的.
from fontTools.ttLib import TTFont
def get_num_phone(es_str: str):
# 加载字体生成映射关系
path = '123_new_ttf.ttf'
font = TTFont(path)
# font.saveXML('font.xml') # 生成xml文件
# 得到映射关系
bestcmap = font.getBestCmap()
ss = {}
for key, value in bestcmap.items():
keys = hex(key).replace('0x', '').replace("&#x", "") # 10进制转16进制
if value == "zero":
value = 0
elif value == "one":
value = 1
elif value == "one":
value = 1
elif value == "two":
value = 2
elif value == "three":
value = 3
elif value == "four":
value = 4
elif value == "five":
value = 5
elif value == "six":
value = 6
elif value == "seven":
value = 7
elif value == "eight":
value = 8
elif value == "nine":
value = 9
elif value == "hyphen":
value = "-"
ss.update({
keys: value
})
need_re = es_str
list_phone = ""
try:
for item in need_re.split(";"):
if item:
new_item = item.replace("&#x", "")
list_phone += "".join(str(ss[new_item]))
if not list_phone or len(list_phone) < 2:
return None
return list_phone
except Exception as e:
return None
<cmap>
<tableVersion version="0"/>
<cmap_format_4 platformID="0" platEncID="3" language="0">
<map code="0x23" name="numbersign"/><!-- NUMBER SIGN -->
<map code="0x2a" name="asterisk"/><!-- ASTERISK -->
<map code="0x2b" name="plus"/><!-- PLUS SIGN -->
<map code="0x2d" name="hyphen"/><!-- HYPHEN-MINUS -->
<map code="0x2f" name="slash"/><!-- SOLIDUS -->
</cmap_format_4>
<cmap_format_0 platformID="1" platEncID="0" language="0">
<map code="0x23" name="numbersign"/>
<map code="0x2a" name="asterisk"/>
<map code="0x2b" name="plus"/>
<map code="0x2d" name="hyphen"/>
<map code="0x2f" name="slash"/>
</cmap_format_0>
<cmap_format_4 platformID="3" platEncID="1" language="0">
<map code="0x23" name="numbersign"/><!-- NUMBER SIGN -->
<map code="0x2a" name="asterisk"/><!-- ASTERISK -->
<map code="0x2b" name="plus"/><!-- PLUS SIGN -->
<map code="0x2d" name="hyphen"/><!-- HYPHEN-MINUS -->
<map code="0x2f" name="slash"/><!-- SOLIDUS -->
</cmap_format_4>
<cmap_format_12 platformID="3" platEncID="10" format="12" reserved="0" length="76" language="0" nGroups="5">
<map code="0x23" name="numbersign"/><!-- NUMBER SIGN -->
<map code="0x2a" name="asterisk"/><!-- ASTERISK -->
<map code="0x2b" name="plus"/><!-- PLUS SIGN -->
<map code="0x2d" name="hyphen"/><!-- HYPHEN-MINUS -->
<map code="0x2f" name="slash"/><!-- SOLIDUS -->
<map code="0x880fb" name="zero"/><!-- ???? -->
<map code="0x880fc" name="one"/><!-- ???? -->
<map code="0x880fd" name="two"/><!-- ???? -->
<map code="0x880fe" name="three"/><!-- ???? -->
<map code="0x880ff" name="four"/><!-- ???? -->
<map code="0x88100" name="five"/><!-- ???? -->
<map code="0x88101" name="six"/><!-- ???? -->
<map code="0x88102" name="seven"/><!-- ???? -->
<map code="0x88103" name="eight"/><!-- ???? -->
<map code="0x88104" name="nine"/><!-- ???? -->
</cmap_format_12>
</cmap>
读取ttf文件,(再生成xml文件,第一次寻找映射关系是需要做的)
font.getBestCmap()获取映射关系表- 我们观察 xml文件的
cmap段进行研究 ,可以看到我们明确需要的结果 keys = hex(key).replace('0x', '').replace("&#x", "")10进制转16进制 ,会得到映射关系表{'23': 'numbersign', '2a': 'asterisk', '2b': 'plus', '2d': '-', '2f': 'slash', '8826e': 0, '8826f': 1, '88270': 2, '88271': 3, '88272': 4, '88273': 5, '88274': 6, '88275': 7, '88276': 8, '88277': 9}- 和从页面上那些来的结果 进行 逐个匹配调整就行了.
注意的点
webdriver拿下来的页面源码有可能有点问题,所以我用了 soup_text = bs4.BeautifulSoup(driver.page_source, 'lxml').text 的方法来处理源代码 (import bs4)
其他的就是一些小细节上的问题了.基本的思路就是这样的.
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