Python实现带图形界面的炸金花游戏
作者：Hann Yang
炸金花
题目很简单：就是自己写一个程序，实现诈金花游戏的发牌、判断输赢。
规则：
一付扑克牌，去掉大小王，每个玩家发3张牌，最后比大小，看谁赢。
牌型：
豹子：三张一样的牌，如3张6.
顺金：又称同花顺，即3张同样花色的顺子， 如红桃 5、6、7
顺子：又称拖拉机，花色不同，但是顺子，如红桃5、方片6、黑桃7，组成的顺子
对子：2张牌一样
单张：单张最大的是A
版型大小顺序： 豹子>顺金>顺子>对子>单张
从网上百科到的诈金花各种牌型的出现概率，一起放进代码中增加一点趣味小知识。你可能不知道豹子出现的概率比同花顺大，实际打牌时同花顺反而比豹子小；顺子出现的概率比金花小，实际打牌时顺子反而比金花小；最大牌为5、6、7的单张牌型出现的概率都要比金花和顺子小，所以有的地方额外规定同一局中拿到“235”三张牌要比同局的豹子大。
回到正题，直接上代码，主要2个函数：一个计分、一个比大小
from random import shuffle as DealCards
Players = 5 #人数
pkPacks = 1 #扑克副数
W = "单张","对子","顺子","金花","顺金","豹子"
X = 74.38, 16.94, 3.26, 4.96, 0.22, 0.24 #出现概率
Y = 0.54, 1.36, 2.44, 3.8, 5.43, 7.33, 9.5, 11.95, 14.66, 17.38 #单张概率
V = *(str(i) for i in range(2,10)),*'TJQKA' #T代表10
F = '♠', '♥', '♣', '♦'
P = [f+v for f in F for v in V]*pkPacks
def Scores(pokers):
f,p = [],[]
for poker in pokers:
f.append(F.index(poker[0])+1)
p.append(V.index(poker[1])+2)
t = sorted(p)
if len(set(t))==1:
return 500_0000+t[0] #豹子
elif len(set(t))==2: #对子
if t[0]==t[1]: #对子一样大比较剩下的单张
return (100+t[1])*10000+t[2]
else:
return (100+t[1])*10000+t[0]
else:
if t[0]+1==t[1]==t[2]-1:
if len(set(f))==1:
return 400_0000+t[2] #顺金(同花顺)
else:
return 200_0000+t[2] #顺子
else:
if len(set(f))==1:
return ((300+t[2])*100+t[1])*100+t[0] #金花
else:
return (t[2]*100+t[1])*100+t[0] #单张
def WhoWins(P):
Pokers,Winner = [],[]
for i in range(0,3*Players,3):
Pokers.append(P[i:i+3])
for i,p in enumerate(Pokers,1):
win = Scores(p)
idx = win//100_0000
print(f"Player{i}: {*p,} - {W[idx]}")
Winner.append(win)
win = max(Winner) #没有判断“一样大”，如是则谁在前谁为大
idx = Winner.index(win)
big = win//10000
win = big//100
per = X[win] if win else Y[big-5]
pok = W[win] if win else '单'+V[big-2]
print(f"【Player{idx+1} win!】--> {*Pokers[idx],} {pok}({per}%)\n")
return P[3*Players:] #去掉每一局已发的牌
if __name__ == '__main__':
DealCards(P) #以随机洗牌来模拟发牌
#Players = int(input('请输入参加的人数？'))
PlayersMax = 52*pkPacks//3+1
if not 0<Players<PlayersMax:
print(f'请注意：参与人数的范围 0 < Players < {PlayersMax} ！')
else:
count = 1
while len(P)>=3*Players: #所有牌(52*PokerPairs)发不够一局为止
print(f'第{count}局：')
count += 1
P = WhoWins(P)运行结果：
第1局：
Player1: ('♥Q', '♣2', '♣8') - 单张
Player2: ('♦T', '♥7', '♠6') - 单张
Player3: ('♣4', '♠4', '♦2') - 对子
Player4: ('♠5', '♠9', '♥6') - 单张
Player5: ('♠7', '♠3', '♣5') - 单张
【Player3 win!】--> ('♣4', '♠4', '♦2') 对子(16.94%)
第2局：
Player1: ('♥2', '♥8', '♦4') - 单张
Player2: ('♦9', '♦3', '♥A') - 单张
Player3: ('♠J', '♣A', '♦K') - 单张
Player4: ('♠8', '♥9', '♥T') - 顺子
Player5: ('♣7', '♣9', '♣T') - 金花
【Player5 win!】--> ('♣7', '♣9', '♣T') 金花(4.96%)
第3局：
Player1: ('♦7', '♦J', '♠2') - 单张
Player2: ('♥J', '♦A', '♥K') - 单张
Player3: ('♥4', '♥5', '♦6') - 顺子
Player4: ('♣Q', '♣J', '♠T') - 顺子
Player5: ('♣K', '♦8', '♦5') - 单张
【Player4 win!】--> ('♣Q', '♣J', '♠T') 顺子(3.26%)
扩展
学习要举一反三，做完题目想到把这个程序的界面图形化。无非就是把牌型对应列表下标从下图中索引取出相应的图片来对应到Image控件上；想要输出的文字对应到text控件上；再整2个button控件绑定对应的事件动作。(代码中有第3个button是我测试用的)
牌型图： Pokers.png
初始界面：
发牌界面：
开牌界面：
PokersV1.py 完整源代码：
import tkinter as tk
from PIL import Image,ImageTk
from time import sleep
from random import shuffle as DealCards
Players = 4 #人数
pkPacks = 1 #扑克副数
isReady = True
W = "单张","对子","顺子","金花","顺金","豹子"
X = 74.38, 16.94, 3.26, 4.96, 0.22, 0.24 #出现概率
Y = 0.54, 1.36, 2.44, 3.8, 5.43, 7.33, 9.5, 11.95, 14.66, 17.38 #单张概率
V = *(str(i) for i in range(2,10)),*'TJQKA' #T代表10
F = '♠', '♥', '♣', '♦'
def loadCards():
infile = Image.open("pokers.png")
Images = []
for j in range(4):
image = []
for i in range(15):
box = infile.crop((i*100,j*150,i*100+100,j*150+150))
img = ImageTk.PhotoImage(image=box)
image.append(img)
Images.append(image)
infile.close()
return Images
def dealCards():
global cv,cards,isReady,P,Pokers
if not isReady:
return
cv.itemconfig(txt1, text="")
cv.itemconfig(txt2, text="")
if len(Pokers):
for j in range(3):
for i in range(4):
cv.itemconfig(cards[i][j], image=Cards[0][0])
cv.update()
sleep(0.5)
for j in range(3):
for i in range(4):
cv.itemconfig(cards[i][j], image=Cards[1][0])
cv.update()
sleep(0.3)
if len(P)==0 or len(P)<12:
P = [f+v for f in F for v in V]*pkPacks
DealCards(P)
isReady = False
def playCards():
global cv,isReady,P,Pokers,cards,Cards
if isReady:
return
P = WhoWins(P)
for i,pok in enumerate(Pokers):
for j,p in enumerate(pok):
x = F.index(p[0])
y = V.index(p[1])
#print(x,y,'-',i,j)
cv.itemconfig(cards[i][j], image=Cards[x][y+2])
cv.update()
isReady = True
def Scores(pokers):
f,p = [],[]
for poker in pokers:
f.append(F.index(poker[0])+1)
p.append(V.index(poker[1])+2)
t = sorted(p)
if len(set(t))==1:
return 500_0000+t[0] #豹子
elif len(set(t))==2: #对子
if t[0]==t[1]: #对子一样大比较剩下的单张
return (100+t[1])*10000+t[2]
else:
return (100+t[1])*10000+t[0]
else:
if t[0]+1==t[1]==t[2]-1:
if len(set(f))==1:
return 400_0000+t[2] #顺金(同花顺)
else:
return 200_0000+t[2] #顺子
else:
if len(set(f))==1:
return ((300+t[2])*100+t[1])*100+t[0] #金花
else:
return (t[2]*100+t[1])*100+t[0] #单张
def WhoWins(P):
global cv,txt1,txt2,Pokers
Pokers,Winner = [],[]
for i in range(0,3*Players,3):
Pokers.append(P[i:i+3])
for i,p in enumerate(Pokers,1):
win = Scores(p)
idx = win//100_0000
print(f"Player{i}: {*p,} - {W[idx]}")
Winner.append(win)
win = max(Winner) #没有判断“一样大”，如是则谁在前谁为大
idx = Winner.index(win)
big = win//10000
win = big//100
per = X[win] if win else Y[big-5]
pok = W[win] if win else '单'+V[big-2]
text1 = f"【Player{idx+1} win!】"
text2 = f"{pok}{*Pokers[idx],} {per}%\n"
print(text1,'--> ',text2)
cv.itemconfig(txt1, text=text1)
cv.itemconfig(txt2, text=text2)
return P[3*Players:] #去掉每一局已发的牌
def test():
global Pokers
print("测试：",Pokers)
if __name__ == '__main__':
root = tk.Tk()
root.geometry('1024x768')
root.title('诈金花')
cv = tk.Canvas(root, width=1024, height=680, bg='darkgreen')
cv.pack()
Pokers = []
Cards = loadCards()
cards = [[None]*3 for _ in range(4)]
P = [f+v for f in F for v in V]*pkPacks
DealCards(P)
x1, x2, x3 = 400, 80, 730
y1, y2, y3 = 100, 550, 320
dx1,dx2,dy = 105, 105, 0
imgxy = [[(x1,y1),(x1+dx1,y1),(x1+2*dx1,y1)],[(x3,y3),(x3+dx2,y3+dy),(x3+2*dx2,y3+dy*2)],
[(x1,y2),(x1+dx1,y2),(x1+2*dx1,y2)],[(x2,y3),(x2+dx2,y3+dy),(x2+2*dx2,y3+dy*2)]]
for x,lst in enumerate(imgxy):
for y,coord in enumerate(lst):
cards[x][y] = cv.create_image(coord, image=Cards[0][0])
cv.create_rectangle(coord[0]-50,coord[1]-75,coord[0]+50,coord[1]+75)
tx,ty = coord[0]-100,coord[1]+92
cv.create_text(tx,ty, text=f'Player{x+1}', fill='white')
btn = [None]*3
btn[0] = tk.Button(root,text='发牌',command=dealCards,width=10)
btn[1] = tk.Button(root,text='开牌',command=playCards,width=10)
btn[2] = tk.Button(root,text='测试',command=test,width=10)
for i in range(3):
btn[i].place(y=710, x=350+i*110)
txt1 = cv.create_text(510,300, fill='red', font=("宋体", 16))
txt2 = cv.create_text(510,360, fill='red', font=("宋体", 10))
root.mainloop()【编译程序】
Windows的Cmd窗口中执行如下命令，Mac系统自行百度：
pyinstaller -F exam.py --noconsole
注意：记得把上面的牌型图保存为Pokers.png和代码放一起运行。
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