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python实现简单猜单词游戏

作者:Sunmer_days

这篇文章主要为大家详细介绍了python实现简单猜单词游戏,文中示例代码介绍的非常详细,具有一定的参考价值,感兴趣的小伙伴们可以参考一下

本文实例为大家分享了python实现猜单词游戏的具体代码,供大家参考,具体内容如下

电脑根据单词列表随机生成一个单词,打印出这个单词长度个 ‘ _ ' ,玩家随机输入一个这个单词可能包含的英文字母,如果玩家猜对了,电脑则会在正确的空格处填写这个字母,如果没有猜对,游戏次数就减一。如果玩家在游戏次数减为零前猜对这个单词的所有字母,则玩家获胜,否则玩家输掉比赛。

from random import*
words = 'tiger lion wolf elephant zebra ducksheep rabbit mouse'.split()
 
#得到要猜的神秘单词
def getWord(wordList):
 n = randint(0,len(wordList)-1)
 return wordList[n]
 
#游戏界面
def display(word,wrongLetters,rightLetters,chance):
 print('你还有{:n}次机会'.format(chance).center(40,'-'))
 print('已经猜错的字母:'+ wrongLetters)
 print()
 blanks = '_'*len(word)
 for i in range(len(word)):
  if word[i] in rightLetters:
   blanks = blanks[:i] + word[i] +blanks[i+1:]
 for i in blanks:
  print(i+' ',end='')
 print()
 print()
 
#从玩家的输入得到一个猜测的字母
def getLetter(alreadyGuessed):
 while True:
  print('请输入一个可能的字母:')
  guess = input()
  guess = guess.lower()
  if guess[0] in alreadyGuessed:
   print('你已经猜过这个字母了!')
  elif guess[0] not in 'qwertyuiopasdfghjklzxcvbnm':
   print('请输入一个英文字母!(a-z)')
  else:
   return guess[0]
  
#是否再玩一次
def playAgain():
 print('是否在玩一次?(y/n)')
 s = input()
 s = s.lower()
 if s[0] == 'y':
  return 1
 return 0
 
#游戏初始化
wrongLetters = ''
rightLetters = ''
word = getWord(words)
chance = 6 #初始为6次机会
done = False
 
while True:
 display(word,wrongLetters,rightLetters,chance)
 
 guess = getLetter(wrongLetters+rightLetters)
 
 if guess in word:
  rightLetters = rightLetters+ guess
  foundAll = True
  for i in range(len(word)):
   if word[i] not in rightLetters:
    foundAll = False
    break
  if foundAll:
   print('你真棒,这个单词就是'+ word +',你赢了!')
   done = True
 else:
   wrongLetters = wrongLetters + guess
   chance = chance - 1
   if chance == 0:
    display(word,wrongLetters,rightLetters,chance)
    print("你已经没有机会了!你一共猜错了"+str(len((wrongLetters))+"次,猜对了"+str(len(rightLetters))+"次,正确的单词是:"+ word)
    done = True
 if done:
  if playAgain():
   wrongLetters = ''
   rightletters = ''
   word = getWord(words)
   chance = 6 #初始为6次机会
   done = 0
  else:
   break

再为大家提供一段代码:python猜单词游戏,作为补充,感谢原作者的分享。

import random
WORDS = ("math","english","china","history")
right = 'Y'
print("欢迎参加猜单词游戏!")
 
while right=='Y' or right=='y':
  word=random.choice(WORDS)
  correct=word
  newword = ''
  while word:
    pos=random.randrange(len(word))
    newword+=word[pos]
    #将word单词下标为pos的字母去掉,取pos前面和后面的字母组成新的word
    word = word[:pos]+word[(pos+1):] #保证随机字母出现不会重复
  print("你要猜测的单词为:",newword)
  guess = input("请输入你的答案:")
  count=1
  while count<5:
    if guess!=correct:
      guess = input("输入的单词错误,请重新输入:")
      count+=1
    else :
      print("输入的单词正确,正确单词为:",correct)
      break
  if count == 5:
    print("您已猜错5次,正确的单词为:",correct)
 
  right = input("是否继续,Y/N:")

以上就是本文的全部内容,希望对大家的学习有所帮助,也希望大家多多支持脚本之家。

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