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Shell脚本传参数方法总结

投稿：junjie

这篇文章主要介绍了Shell脚本传参数方法总结,本文着重讲解传递固定个数参数的方法、可变个数参数的方法两部份内容,需要的朋友可以参考下

一、接收固定长度的参数

复制代码 代码如下:

[root@svn shell_example]# cat params.sh
#!/bin/bash
#传参测试脚本
echo "My name is `basename $0` -I was called as $0"
echo "My first parameter is : $1"
echo "My second parameter is : $2"

空参数执行
复制代码 代码如下:

[root@svn shell_example]# sh params.sh
My name is params.sh -I was called as params.sh
My first parameter is :
My second parameter is :

传递2个参数执行
复制代码 代码如下:

[root@svn shell_example]# sh params.sh one two
My name is params.sh -I was called as params.sh
My first parameter is : one
My second parameter is : two

二、那如果还有参数怎么办呢?还要一个个加上来吗?答案是否定的

以下用法应该不陌生,就是直接执行脚本本身,没有附带任何参数,那么脚本讲抛出帮助信息.即怎么使用此脚本.见红字部分

复制代码 代码如下:

[root@svn shell_example]# sh params_v2.sh
My name is params_v2.sh -I was called as params_v2.sh
I was called with 0 parameters.
Usage: params_v2.sh first second
You provided 0 parameters,but 2 are required.

代码如下
复制代码 代码如下:

[root@svn shell_example]# cat params_v2.sh
#!/bin/bash
# 这是个测试脚本传参的测试例子

echo "My name is `basename $0` -I was called as $0"
echo "I was called with $# parameters."

if [ "$#" -eq "2" ];then
    echo "My first parameter is $1"
    echo "My second parameter is $2"
else
    echo "Usage: `basename $0` first second"
    echo "You provided $# parameters,but 2 are required."
fi

详细的执行过程如下
不传参数执行

复制代码 代码如下:

[root@svn shell_example]# sh params_v2.sh
My name is params_v2.sh -I was called as params_v2.sh
I was called with 0 parameters.
Usage: params_v2.sh first second
You provided 0 parameters,but 2 are required.

传递3个参数执行
复制代码 代码如下:

[root@svn shell_example]# sh params_v2.sh one two three
My name is params_v2.sh -I was called as params_v2.sh
I was called with 3 parameters.
Usage: params_v2.sh first second
You provided 3 parameters,but 2 are required.

传递2个参数执行
复制代码 代码如下:

[root@svn shell_example]# sh params_v2.sh one two
My name is params_v2.sh -I was called as params_v2.sh
I was called with 2 parameters.
My first parameter is one
My second parameter is two

问题来了,要是后期还要加参数怎么办呢?或者我也不确定到底会传几个参数.
解决方法如下,详细执行结果如下

复制代码 代码如下:

[root@svn shell_example]# cat manyparams.sh
#!/bin/bash
#这是个测试脚本传N个参数的例子

echo "我的名字是 `basename $0` - 我是调用自 $0"
echo "我有 $# 参数"

count=1
while [ "$#" -ge "1" ];do
    echo "参数序号为 $count 是 $1"
    let count=count+1
    shift
done

一个参数执行

[root@svn shell_example]# sh manyparams.sh one

我的名字是 manyparams.sh - 我是调用自 manyparams.sh
我有 1 参数
参数序号为 1 是 one

5个参数执行

复制代码 代码如下:

[root@svn shell_example]# sh manyparams.sh one two three four five

我的名字是 manyparams.sh - 我是调用自 manyparams.sh
我有 5 参数
参数序号为 1 是 one
参数序号为 2 是 two
参数序号为 3 是 three
参数序号为 4 是 four
参数序号为 5 是 five

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