Shell实现的iptables管理脚本分享
投稿：junjie
这篇文章主要介绍了Shell实现的iptables管理脚本分享,本文脚本实现了添加、删除、查看、停止、启动等,需要的朋友可以参考下
以前的脚本是用save模式，现在把命令附加到一个文件里面，这样的话，可以方便的二次修改什么的
脚本基本是这样的，大家可以跟自己的情况再次修改~ 增加功能什么的。
复制代码 代码如下:
#!/bin/bash
while true
do
clear
echo "----------------------menu----------------------"
echo "(1) service iptables restart"
echo "(2) iptables add"
echo "(3) iptables delete"
echo "(4) iptables stop"
echo "(5) iptables save(不推荐使用这种模式)"
echo "(6) iptables status"
echo "(7) iptables ACL list"
echo "(0) exit"
echo "会在当前的目录下生成一个fw.sh文件"
echo "-------------------------------------------------"
echo -n "enter you chose[0-7]:"
read num
if [ ${num} -lt 0 -o ${num} -gt 7 ]
then
echo "this is not between 0-7"
else
if [ "${num}" == "1" ]
then
service iptables restart&
else
if [ "${num}" == "2" ]
#######################################################
then
while [ "1" == "1" ]
do
clear
echo "----------------------add ACL----------------------"
echo "(1) 针对源IP放行添加"
echo "(2) 针对服务器端口放行添加"
echo "(3) 针对有端口和服务的ACL添加（这里要参数IP和端口 例如 0/0 80）"
echo "(4) 自定义添加"
echo "(5) 退回上一级"
echo "-------------------------------------------------"
echo -n "enter you chose[0-4]:"
read aclnum
if [ "${aclnum}" == "1" ]
then
read ip
iptables -A INPUT -s ${ip} -p tcp --dport 22 -j ACCEPT
echo "iptables -A INPUT -s ${ip} -p tcp --dport 22 -j ACCEPT" >>fw.sh
# service iptables save
elif [ "${aclnum}" == "2" ]
then
rad ip
iptables -A INPUT -p tcp --dport ${IP} -j ACCEPT
echo "iptables -A INPUT -p tcp --dport ${IP} -j ACCEPT" >>fw.sh
# service iptables save
elif [ "${aclnum}" == "3" ]
then
read ip port
iptables -A INPUT -p tcp -s ${ip} --dport ${port} -j ACCEPT
echo "iptables -A INPUT -p tcp -s ${ip} --dport ${port} -j ACCEPT" >>fw.sh
# service iptables save
elif [ "${aclnum}" == "4" ]
then
read addacl
`${addacl}`
service iptables save
else
break
fi
echo -n "是否想继续添加: [y/n]:"
read contine
if [ "${contine}" == "n" -o "${contine}" == "N" ]
then
break
fi
done
#######################################################
else
if [ "${num}" == "3" ]
then
while [ "1" == "1" ]
do
clear
echo "---------------------delete ACL----------------------"
echo "(1) 针对源ip删除"
echo "(2) 针对端口删除"
echo "(3) 针对有端口和服务的ACL删除"
echo "(4) 自定义删除"
echo "(5) 退回上一级"
echo "-------------------------------------------------"
echo -n "enter you chose[0-5]:"
read aclnum
if [ "${aclnum}" == "1" ]
then
read ip
iptables -D INPUT -s ${ip} -p tcp --dport 22 -j ACCEPT
echo "iptables -D INPUT -s ${ip} -p tcp --dport 22 -j ACCEPT" >>fw.sh
# service iptables save
elif [ "${aclnum}" == "2" ]
then
read port
iptables -D INPUT -p tcp --dport ${port} -j ACCEPT
echo "iptables -D INPUT -p tcp --dport ${port} -j ACCEPT" >>fw.sh
# service iptables save
elif [ "${aclnum}" == "3" ]
then
read ip port
iptables -D INPUT -p tcp -s ${ip} --dport ${port} -j ACCEPT
echo "iptables -D INPUT -p tcp -s ${ip} --dport ${port} -j ACCEPT" >>fw.sh
# service iptables save
elif [ "${aclnum}" == "4" ]
then
read deleteacl
`${deleteacl}`
service iptables save
else
break
fi
echo -n "是否想继续添加: [y/n]:"
read contine
if [ "${contine}" == "n" -o "${contine}" == "N" ]
then
break
fi
done
###################################################################
else
if [ "${num}" == "4" ]
then
echo -e "`service iptables stop&` "
else
if [ "${num}" == "5" ]
then
echo -e "`service iptables save&`"
else
if [ "${num}" == "6" ]
then
echo -e "`service iptables status&`"
else
if [ "${num}" == "7" ]
then
while [ "1" == "1" ]
do
clear
echo "---------------------list ACL----------------------"
echo "(1) 查看当前正在使用的规则集"
echo "(2) 查看每个策略或每条规则、每条链的简单流量统计"
echo "(3) 查看NAT表"
echo "(4) 自定义查看"
echo "(5) 退回上一级"
echo "-------------------------------------------------"
echo -n "enter you chose[0-5]:"
read aclnum
if [ "${aclnum}" == "1" ]
then
iptables -L
elif [ "${aclnum}" == "2" ]
then
iptables -L -n -v
elif [ "${aclnum}" == "3" ]
then
iptables -L -t nat
elif [ "${aclnum}" == "4" ]
then
read listacl
`${listacl}`
else
break
fi
echo -n "是否想继续添加: [y/n]:"
read contine
if [ "${contine}" == "n" -o "${contine}" == "N" ]
then
break
fi
done
################################################
else
exit
fi
fi
fi
fi
fi
fi
fi
fi
echo -n "Do you contine [y/n]:"
read contine
if [ "${contine}" == "n" -o "${contine}" == "N" ]
then
exit
fi
done