python

关注公众号 jb51net

关闭
首页 > 脚本专栏 > python > 多cpu并行编程

python中的多cpu并行编程

作者:toforu

这篇文章主要介绍了python中的多cpu并行编程,具有很好的参考价值,希望对大家有所帮助。如有错误或未考虑完全的地方,望不吝赐教

多cpu并行编程

安装

pip install pp

使用

#-*- coding: UTF-8 -*-
import math, sys, time
import pp
def IsPrime(n):
    """返回n是否是素数"""
    if not isinstance(n, int):
        raise TypeError("argument passed to is_prime is not of 'int' type")
    if n < 2:
        return False
    if n == 2:
        return True
    max = int(math.ceil(math.sqrt(n)))
    i = 2
    while i <= max:
        if n % i == 0:
            return False
        i += 1
    return True
def SumPrimes(n):
    for i in xrange(15):
        sum([x for x in xrange(2,n) if IsPrime(x)])
    """计算从2-n之间的所有素数之和"""
    return sum([x for x in xrange(2,n) if IsPrime(x)])
inputs = (100000, 100100, 100200, 100300, 100400, 100500, 100600, 100700)
# start_time = time.time()
# for input in inputs:
#     print SumPrimes(input)
# print '单线程执行,总耗时', time.time() - start_time, 's'
# # tuple of all parallel python servers to connect with
ppservers = ()
#ppservers = ("10.0.0.1",)
if len(sys.argv) > 1:
    ncpus = int(sys.argv[1])
    # Creates jobserver with ncpus workers
    job_server = pp.Server(ncpus, ppservers=ppservers)
else:
    # Creates jobserver with automatically detected number of workers
    job_server = pp.Server(ppservers=ppservers)
print "pp 可以用的工作核心线程数", job_server.get_ncpus(), "workers"
start_time = time.time()
jobs = [(input, job_server.submit(SumPrimes,(input,), (IsPrime,), ("math",))) for input in inputs]#submit提交任务
for input, job in jobs:
    print "Sum of primes below", input, "is", job()# job()获取方法执行结果
print "多线程下执行耗时: ", time.time() - start_time, "s"
job_server.print_stats()#输出执行信息

执行结果

pp 可以用的工作核心线程数 4 workers
Sum of primes below 100000 is 454396537
Sum of primes below 100100 is 454996777
Sum of primes below 100200 is 455898156
Sum of primes below 100300 is 456700218
Sum of primes below 100400 is 457603451
Sum of primes below 100500 is 458407033
Sum of primes below 100600 is 459412387
Sum of primes below 100700 is 460217613
多线程下执行耗时:  15.4971420765 s
Job execution statistics:
 job count | % of all jobs | job time sum | time per job | job server
         8 |        100.00 |      60.9828 |     7.622844 | local
Time elapsed since server creation 15.4972219467
0 active tasks, 4 cores

submit 函数定义

def submit(self, func, args=(), depfuncs=(), modules=(),
        callback=None, callbackargs=(), group='default', globals=None):
    """Submits function to the execution queue
 
        func - function to be executed  执行的方法
        args - tuple with arguments of the 'func' 方法传入的参数,使用元组
        depfuncs - tuple with functions which might be called from 'func' 传入自己写的方法 ,元组
        modules - tuple with module names to import  传入 模块
        callback - callback function which will be called with argument
                list equal to callbackargs+(result,)
                as soon as calculation is done
        callbackargs - additional arguments for callback function
        group - job group, is used when wait(group) is called to wait for
        jobs in a given group to finish
        globals - dictionary from which all modules, functions and classes
        will be imported, for instance: globals=globals()
    """

多核cpu并行计算

# 多进程
import multiprocessing as mp
def job(q, a, b):
    print('aaa')
    q.put(a**1000+b*1000)  # 把计算结果放到队列
# 多进程
if __name__ == '__main__':
    q = mp.Queue()  # 一个队列
    p1 = mp.Process(target=job, args=(q, 100, 200))
    p2 = mp.Process(target=job, args=(q, 100, 200))
    p1.start()
    p1.join()
    # print(p1.ident)
    p2.start()
    p2.join()
    res = q.get() + q.get()  # 读取队列,这里面保存了两次计算得到的结果
    print('result:', res)

以上为个人经验,希望能给大家一个参考,也希望大家多多支持脚本之家。

您可能感兴趣的文章:
阅读全文