python二叉树常用算法总结
作者:我是一颗大西瓜
这篇文章主要分享的是python二叉树常用算法,二叉树的递归思想很重要,还有递归的复杂度分析,需下面文章就来详细解说该算法,要的朋友可以参考一下
1.1 二叉树的初始化
#initial of BinaryTree class BinaryTree: def __init__(self,rootObj): self.val = rootObj self.left = None self.right = None def insertLeft(self,newNode): if self.left == None: self.left = BinaryTree(newNode) else: t = BinaryTree(newNode) t.left = self.left self.left = t def insertRight(self,newNode): if self.right == None: self.right = BinaryTree(newNode) else: t = BinaryTree(newNode) t.right = self.right self.right = t
1.2 创建一个二叉树
#create a BinaryTree [18,7,11,3,4,5,6,#,#,#,#,1,3,2,4] # 18 # 7 11 #3 4 5 6 # 1 3 2 4 root = BinaryTree(18) root.left = BinaryTree(7) root.right = BinaryTree(11) root.left.left = BinaryTree(3) root.left.right = BinaryTree(4) root.right.left = BinaryTree(5) root.right.right = BinaryTree(6) root.right.left.left = BinaryTree(1) root.right.left.right = BinaryTree(3) root.right.right.left = BinaryTree(2) root.right.right.right = BinaryTree(4)
1.3 前序遍历
#递归版本 def PreOrder(self, node): if node: print(node.val) self.PreOrder(node.left) self.PreOrder(node.right) #循环版本 def PreOrderLoop(self, node): if node == None: return stack =[] print(node.val) stack.append(node) node = node.left while stack!=[] or node: while node: print(node.val) stack.append(node) node = node.left node = stack[-1].right stack.pop() #ouput: 18 7 3 4 11 5 1 3 6 2 4
1.4 中序遍历
#递归版本 def InOrder(self, node): if node: self.InOrder(node.left) print(node.val) self.InOrder(node.right) #循环版本 def InOrderLoop(self, node): if node == None: return None stack = [] stack.append(node) node = node.left while stack!=[] or node: while node: stack.append(node) node = node.left print(stack[-1].val) node = stack[-1].right stack.pop() #output:3 7 4 18 1 5 3 11 2 6 4
1.5 后序遍历
#递归 def PostOrder(self, node): if node: self.PostOrder(node.left) self.PostOrder(node.right) print(node.val) #非递归 def PostOrderLoop(self, node): if node == None: return stack =[] stack.append(node) pre = None while stack!=[]: node = stack[-1] if ((node.left==None and node.right==None) or (pre and (pre == node.left or pre ==node.right))): print(node.val) pre = node stack.pop() else: if node.right: stack.append(node.right) if node.left: stack.append(node.left) #output:3 4 7 1 3 5 2 4 6 11 18
1.6 层序遍历
def LevelOrder(self, node): if node == None: return stack = [] stack.append(node) while stack!=[]: node = stack[0] if node.left: stack.append(node.left) if node.right: stack.append(node.right) print(node.val) stack.pop(0) output: 18 7 11 3 4 5 6 1 3 2 4
1.7 计算节点数
#递归版本 def CountNode(self, root): if root == None: return 0 return self.CountNode(root.left) + self.CountNode(root.right) + 1 #非递归版本 def CountNodeNotRev(self, root): if root == None: return 0 stack = [] stack.append(root) index = 0 while index<len(stack): if stack[index].left: stack.append(stack[index].left) if stack[index].right: stack.append(stack[index].right) index += 1 print(len(stack)) output: 11
1.8 计算树的深度
def getTreeDepth(self, root): if root == None: return 0 left = self.getTreeDepth(root.left) + 1 right = self.getTreeDepth(root.right) + 1 return left if left>right else right
1.9 计算树的叶子树
def countLeaves(self, root): if root == None: return 0 if root.left==None and root.right==None: return 1 return self.countLeaves(root.left)+self.countLeaves(root.right)
1.10 获取第K层节点数
def getKLevel(self, root, K): if root == None: return 0 if K == 1: return 1 return self.getKLevel(root.left, K-1)+self.getKLevel(root.right, K-1)
1.11 判断两颗二叉树是否相同
def StrucCmp(self, root1, root2): if root1 == None and root2 == None: return True elif root1 ==None or root2 == None: return False return self.StrucCmp(root1.left, root2.left) and self.StrucCmp(root1.right, root2.right)
1.12 二叉树的镜像
def Mirror(self, root): if root == None: return tmp = root.left root.left = root.right root.right = tmp self.Mirror(root.left) self.Mirror(root.right)
1.13 找最低公共祖先节点
def findLCA(self, root, node1, node2): if root == None: return if root == node1 or root == node2: return root left = self.findLCA(root.left, node1, node2) right = self.findLCA(root.right, node1, node2) if left and right: return root return left if left else right
1.14 获取两个节点的距离
def getDist(self, root, node1, node2): lca = self.findLCA(root, node1, node2) #找最低公共祖宗节点 level1 = self.FindLevel(lca, node1) #祖节点到两个节点的距离 level2 = self.FindLevel(lca, node2) return level1+level2 def FindLevel(self, node, target): if node == None: return -1 if node == target: return 0 level = self.FindLevel(node.left, target) if level == -1: level = self.FindLevel(node.right, target) if level != -1: return level + 1 return -1
1.15 找一个节点的所有祖宗节点
def findAllAncestor(self, root, target): if root == None: return False if root == target: return True if self.findAllAncestor(root.left, target) or self.findAllAncestor(root.right, target): print(root.val) return True return False
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