python数字转对应中文的方法总结
作者:藏色散人
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本文操作环境:
windows7系统,DELL G3电脑,python3.5版
python实现将阿拉伯数字转换成中文
第一种转换方式:
1 --> 一 12 --> 一二 def num_to_char(num): """数字转中文""" num=str(num) new_str="" num_dict={"0":u"零","1":u"一","2":u"二","3":u"三","4":u"四","5":u"五","6":u"六","7":u"七","8":u"八","9":u"九"} listnum=list(num) # print(listnum) shu=[] for i in listnum: # print(num_dict[i]) shu.append(num_dict[i]) new_str="".join(shu) # print(new_str) return new_str
第二种转换方式:
1 --> 一 12 --> 十二 23 --> 二十三 _MAPPING = (u'零', u'一', u'二', u'三', u'四', u'五', u'六', u'七', u'八', u'九', u'十', u'十一', u'十二', u'十三', u'十四', u'十五', u'十六', u'十七',u'十八', u'十九') _P0 = (u'', u'十', u'百', u'千',) _S4 = 10 ** 4 def _to_chinese4(num): assert (0 <= num and num < _S4) if num < 20: return _MAPPING[num] else: lst = [] while num >= 10: lst.append(num % 10) num = num / 10 lst.append(num) c = len(lst) # 位数 result = u'' for idx, val in enumerate(lst): val = int(val) if val != 0: result += _P0[idx] + _MAPPING[val] if idx < c - 1 and lst[idx + 1] == 0: result += u'零' return result[::-1]
实例扩展:
#!/usr/bin/python #-*- encoding: utf-8 -*- import types class NotIntegerError(Exception): pass class OutOfRangeError(Exception): pass _MAPPING = (u'零', u'一', u'二', u'三', u'四', u'五', u'六', u'七', u'八', u'九', ) _P0 = (u'', u'十', u'百', u'千', ) _S4, _S8, _S16 = 10 ** 4 , 10 ** 8, 10 ** 16 _MIN, _MAX = 0, 9999999999999999 def _to_chinese4(num): '''转换[0, 10000)之间的阿拉伯数字 ''' assert(0 <= num and num < _S4) if num < 10: return _MAPPING[num] else: lst = [ ] while num >= 10: lst.append(num % 10) num = num / 10 lst.append(num) c = len(lst) # 位数 result = u'' for idx, val in enumerate(lst): if val != 0: result += _P0[idx] + _MAPPING[val] if idx < c - 1 and lst[idx + 1] == 0: result += u'零' return result[::-1].replace(u'一十', u'十') def _to_chinese8(num): assert(num < _S8) to4 = _to_chinese4 if num < _S4: return to4(num) else: mod = _S4 high, low = num / mod, num % mod if low == 0: return to4(high) + u'万' else: if low < _S4 / 10: return to4(high) + u'万零' + to4(low) else: return to4(high) + u'万' + to4(low) def _to_chinese16(num): assert(num < _S16) to8 = _to_chinese8 mod = _S8 high, low = num / mod, num % mod if low == 0: return to8(high) + u'亿' else: if low < _S8 / 10: return to8(high) + u'亿零' + to8(low) else: return to8(high) + u'亿' + to8(low) def to_chinese(num): if type(num) != types.IntType and type(num) != types.LongType: raise NotIntegerError(u'%s is not a integer.' % num) if num < _MIN or num > _MAX: raise OutOfRangeError(u'%d out of range[%d, %d)' % (num, _MIN, _MAX)) if num < _S4: return _to_chinese4(num) elif num < _S8: return _to_chinese8(num) else: return _to_chinese16(num) if __name__ == '__main__': print to_chinese(9000)
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