Android基于opencv实现多通道分离与合并
作者：易冬
针对图像多通道的分离与混合，OpenCV 4中提供了split()函数和merge()函数用于解决这些需求。本文讲解一下Android如何调用这些函数实现多通道分离与合并
多通道分离
API
public static void split(Mat m, List<Mat> mv)
- 参数一：m，待分离的多通道图像
- 参数二：mv，分离后的单通道图像
操作
override fun onCreate(savedInstanceState: Bundle?) {
super.onCreate(savedInstanceState)
mBinding = DataBindingUtil.setContentView(this, R.layout.activity_channel_split_merge)
mBgr = Utils.loadResource(this, R.drawable.test)
val imgList = mutableListOf<Mat>()
Core.split(mBgr, imgList)
mChannelB = imgList[0]
mChannelG = imgList[1]
mChannelR = imgList[2]
}
通道合并
API
public static void merge(List<Mat> mv, Mat dst)
- 参数一：mv，需要合并的图像数组，其中每个图像必须拥有相同的尺寸和数据类型
- 参数二：dst，合并后输出的图像，与mv[0]具有相同的尺寸和数据类型，通道数等于所有输入图像的通道数总和
操作
private fun showBGZero() {
val zero = Mat.zeros(mBgr.rows(), mBgr.cols(), CvType.CV_8UC1)
val list = mutableListOf<Mat>()
list.add(zero)
list.add(zero)
list.add(mChannelR)
val result = Mat()
Core.merge(list, result)
showMat(result)
result.release()
}
private fun showBRZero() {
val zero = Mat.zeros(mBgr.rows(), mBgr.cols(), CvType.CV_8UC1)
val list = mutableListOf<Mat>()
list.add(zero)
list.add(mChannelG)
list.add(zero)
val result = Mat()
Core.merge(list, result)
showMat(result)
result.release()
}
private fun showGRZero() {
val zero = Mat.zeros(mBgr.rows(), mBgr.cols(), CvType.CV_8UC1)
val list = mutableListOf<Mat>()
list.add(mChannelB)
list.add(zero)
list.add(zero)
val result = Mat()
Core.merge(list, result)
showMat(result)
result.release()
}
private fun showSwitchBR() {
val zero = Mat.zeros(mBgr.rows(), mBgr.cols(), CvType.CV_8UC1)
val list = mutableListOf<Mat>()
list.add(mChannelR)
list.add(mChannelG)
list.add(mChannelB)
val result = Mat()
Core.merge(list, result)
showMat(result)
result.release()
}
结果
源码
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