python绘制汉诺塔
作者:一个超会写Bug的安太狼
这篇文章主要为大家详细介绍了python绘制汉诺塔,文中示例代码介绍的非常详细,具有一定的参考价值,感兴趣的小伙伴们可以参考一下
本文实例为大家分享了python绘制汉诺塔的具体代码,供大家参考,具体内容如下
源码:
import turtle class Stack: def __init__(self): self.items = [] def isEmpty(self): return len(self.items) == 0 def push(self, item): self.items.append(item) def pop(self): return self.items.pop() def peek(self): if not self.isEmpty(): return self.items[len(self.items) - 1] def size(self): return len(self.items) def drawpole_3(): # 画出汉诺塔的poles t = turtle.Turtle() t.hideturtle() def drawpole_1(k): t.up() t.pensize(10) t.speed(100) t.goto(400 * (k - 1), 100) t.down() t.goto(400 * (k - 1), -100) t.goto(400 * (k - 1) - 20, -100) t.goto(400 * (k - 1) + 20, -100) drawpole_1(0) # 画出汉诺塔的poles[0] drawpole_1(1) # 画出汉诺塔的poles[1] drawpole_1(2) # 画出汉诺塔的poles[2] def creat_plates(n): # 制造n个盘子 plates = [turtle.Turtle() for i in range(n)] for i in range(n): plates[i].up() plates[i].hideturtle() plates[i].shape("square") plates[i].shapesize(1, 8 - i) plates[i].goto(-400, -90 + 20 * i) plates[i].showturtle() return plates def pole_stack(): # 制造poles的栈 poles = [Stack() for i in range(3)] return poles def moveDisk(plates, poles, fp, tp): # 把poles[fp]顶端的盘子plates[mov]从poles[fp]移到poles[tp] mov = poles[fp].peek() plates[mov].goto((fp - 1) * 400, 150) plates[mov].goto((tp - 1) * 400, 150) l = poles[tp].size() # 确定移动到底部的高度(恰好放在原来最上面的盘子上面) plates[mov].goto((tp - 1) * 400, -90 + 20 * l) def moveTower(plates, poles, height, fromPole, toPole, withPole): # 递归放盘子 if height >= 1: moveTower(plates, poles, height - 1, fromPole, withPole, toPole) moveDisk(plates, poles, fromPole, toPole) poles[toPole].push(poles[fromPole].pop()) moveTower(plates, poles, height - 1, withPole, toPole, fromPole) myscreen = turtle.Screen() drawpole_3() n = int(input("请输入汉诺塔的层数并回车:\n")) plates = creat_plates(n) poles = pole_stack() for i in range(n): poles[0].push(i) moveTower(plates, poles, n, 0, 2, 1) myscreen.exitonclick()
效果图:
以上就是本文的全部内容,希望对大家的学习有所帮助,也希望大家多多支持脚本之家。