Python如何动态修改Word文档内容并保留格式样式

pip install docx

pip install pywin32

from docx import Document
import pandas as pd
import json

def replaceText(wb, t, value):
    for x in wb.paragraphs:
        if t in x.text:  # t 尽量短，一个最好，不然这里可能会被拆分 如果替换失败 DEBUG这里查看x.text
            inline = x.runs  # t 修改runs中的字符串 可以保留格式
            for i in range(len(inline)):
                if t in inline[i].text:
                    text = inline[i].text.replace(t, str(value))
                    inline[i].text = text

    for table in wb.tables:  # 遍历文档中的所有表格
        for row in table.rows:  # 遍历表格中的所有行
            for cell in row.cells:  # 遍历行中的所有单元格
                if t in cell.text:
                    for paragraph in cell.paragraphs:
                        if t in paragraph.text:
                            inline = paragraph.runs
                            for i in range(len(inline)):
                                if t in inline[i].text:
                                    text = inline[i].text.replace(t, str(value))
                                    inline[i].text = text

#  word表格居中：在字符串前面拼空格 这里的11是表格不换行的情况下最长可输入的字符数
def getCenterText(text):
    text = text.replace(' ', '')
    for i in range(11 - len(text)):
        text = " " + text
    return text

# 程序入口
if __name__ == '__main__':
    # loan_data = pd.read_excel(r"C:\Users\Administrator\Desktop\排名\汇总.xlsx",
    #                           sheet_name="Sheet1", header=0, names=None, index_col=0)
    # jsonstr = loan_data.to_json(orient='records', force_ascii=False)

    loan_data = [
        {"AME": "张三", "XX": "优秀"},
        {"AME": "李四", "XX": "良好"}
    ]

    for j in loan_data:
        wb = Document(r"C:\Users\Administrator\Desktop\排名\模版.docx")
        replaceText(wb, 'AME', j.get('AME'))  # 把Word中的AME替换成张三、李四
        replaceText(wb, 'XX', getCenterText(j.get('XX')))  # 如果是表格数据要居中
        wb.save(r"C:\Users\Administrator\Desktop\排名\结果(%s).docx" % j.get('AME'))
        print(j.get('AME'))
    print("完成")

from win32com.client import Dispatch
from os import walk

wdFormatPDF = 17
def doc2pdf(input_file):
    word = Dispatch('Word.Application')
    doc = word.Documents.Open(input_file)
    doc.SaveAs(input_file.replace(".docx", ".pdf"), FileFormat=wdFormatPDF)
    doc.Close()
    word.Quit()

# 程序入口
if __name__ == '__main__':
    # 把此文件夹下所有的Word文档转为PDF
    directory = "C:\\Users\\Administrator\\Desktop\\排名"
    for root, dirs, filenames in walk(directory):
        for file in filenames:
            print(file)
            if file.endswith(".doc") or file.endswith(".docx"):
                doc2pdf(str(root + "\\" + file))
    print("全部完成")

import os
import io
from python_docx_replace import docx_replace,docx_get_keys
from docx import Document
from random import randrange
student_list='''1,张三,2202330301
2,李四,2202330302
3,王五,2202330303
'''


review=["思路清晰、语言表达准确，整体表现良好","，准备工作一般，整体表现良好","思路清晰、语言表达一般、回答问题有理论依据，","有个别格式不对的需要修改。"]
score=['70', '88', '81']

students=student_list.split("\n")

# print(students)
students_dict_array=[]

for student in students:
    student_dict={}
    student_dict["name"]=student.split(",")[1]
    student_dict["sid"]=student.split(",")[2]
    students_dict_array.append(student_dict)

print(students_dict_array)

# 图片存放的路径
path = "C:\\BaiduSyncdisk\\大学生信息安全竞赛评分表\\"
def alter(file,name,id,num):
    """
    替换文件中的字符串
    :param file:文件名
    :param old_str:就字符串
    :param new_str:新字符串
    :return:
    """
    doc = Document(file)
    keys = docx_get_keys(doc) # Let's suppose the Word document has the keys: ${name} and ${phone}
    print(keys)  # ['name', 'phone']
# call the replace function with your key value pairs
    docx_replace(doc, name=name,id=id,content=review[randrange(len(review))],score=score[num])
    doc.save(os.path.join(path,"new",file))

 
# 遍历更改文件名
num = 0
for file in os.listdir(path):
    alter(os.path.join(path,file),students_dict_array[num]["name"],students_dict_array[num]["sid"],num)
    os.rename(os.path.join(path,file),os.path.join(path,"选手-"+students_dict_array[num]["sid"][-2:]+students_dict_array[num]["name"]+"-记录表")+".doc")
    num = num + 1