Python实现将字典(列表按列)存入csv文件

import pandas as pd
 
dic1 = {'学号': [6812, 6952, 6905], '姓名': ['一', '二', '三'], '排名': [1, 6, 9]}
df = pd.DataFrame(dic1, index=range(0, 3))
df.to_csv('last.csv', index=False, encoding='gbk')

week1 = ['一', '二', '三', '四', '五', '六', '七']
weekSpend = [50, 40, 30, 60, 45, 55, 67]
day1 = ['m', 't', 'w', 'tu', 'f', 's', 'su']
daySpend = [10, 20, 30, 40, 10, 20, 22]
DF = {'weekName': week1, 'weekSpend': weekSpend, 'dayName': day1, 'daySpend': daySpend}
trydf = pd.DataFrame(DF)
trydf.to_csv('df1.csv', index=False, encoding='gbk', mode='a')

week1 = ['一', '二', '三', '四', '五', '六', '七']
weekSpend = [50, 40, 30, 60, 45, 55, 67]
day1 = ['m', 't', 'w', 'tu', 'f', 's', 'su']
daySpend = [10, 20, 30, 40, 10, 20, 22]
try2df1 = pd.DataFrame(week1)
try2df2 = pd.DataFrame(weekSpend)
try2df3 = pd.DataFrame(day1)
try2df4 = pd.DataFrame(daySpend)
try2df1.to_csv('df2.csv', index=False, encoding='gbk', mode='a')
try2df2.to_csv('df2.csv', index=False, encoding='gbk', mode='a')
try2df3.to_csv('df2.csv', index=False, encoding='gbk', mode='a')
try2df4.to_csv('df2.csv', index=False, encoding='gbk', mode='a')

pd1.to_csv('save.csv', encoding='gbk', index=False, header=None) # 里面有中文就用gbk

import re
import pandas as pd
 
with open('李连jie.txt', 'r', encoding='utf-8') as f:
    data_ = f.readlines()
save_list = []
 
 
def to_scv_():
    print(data_)
    temp_tup = []
    for i in data_:
        find_name_1 = re.findall('([a-zA-Z]+-\d+)\n', i)  # 匹配编号的行(只有编号)
        if len(find_name_1):
            print(find_name_1)
            temp_tup.append(find_name_1[0])
            temp_tup.append('')  # 无名
        else:
            find_name_2 = re.findall('([a-zA-Z]+-\d+) (.*?)\n', i)  # 匹配名称的行(匹配中文)(只有名称)
            if len(find_name_2):
                print(find_name_2)
                temp_tup.append(find_name_2[0][0])
                temp_tup.append(find_name_2[0][1])
                # 顺序不能反，因为2中也有中文，还有编号，所以2查询在前
            else:
                find_name_3 = re.findall('([\u4e00-\u9fa5]+)\n', i)  # 匹配编号 名称的行(编号，名称都有)
                if len(find_name_3):
                    print(find_name_3)
                    temp_tup.append('')  # 无编号
                    temp_tup.append(find_name_3[0])
 
        magnet_ = re.findall('(magnet:.*?)\n', i)  # 匹配磁力
        if len(magnet_):
            temp_tup.append(magnet_[0])
            save_list.append(temp_tup)
            temp_tup = []  # 只有在追加完名称，现在加完磁力才是一个完整的list，这时才清空
 
    print(save_list)
    for i in save_list:
        print(i)
 
    save_dic = ({'编号': row[0], '名称': row[1], '磁力链接': row[2]} for row in save_list)
    pd1 = pd.DataFrame(save_dic)
    pd1.to_csv('mysave.csv', encoding='gbk', index=False, header=None)
 
 
to_scv_()

import pandas as pd
 
data = pd.read_csv('newdata.csv', encoding='utf-8')  # 包含成绩等数据，但不包含班级信息
stu_class = pd.read_csv('班级.csv', encoding='utf-8')  # 仅包含班级和姓名的数据
 
# 使用 merge 函数根据姓名进行合并
merged_data = pd.merge(stu_class, data, on='姓名')
 
# 选择需要的列并重命名
result = merged_data[['姓名', '班级', '体测成绩', '学年平均学分绩点', '综合测评总分排名', '综合测评总分（百分制、精确到小数点后4位）', '学业成绩考核排名']]
result.columns = ['姓名', '班级', '体测', '绩点', '绩点排名', '综测得分', '综测排名']
 
# 将结果保存为 CSV 文件
result.to_csv('最终文件.csv', index=False, encoding='gbk')

import pandas as pd
 
data = pd.read_csv('newdata.csv', encoding='utf-8')  # 含有成绩等的数据，但是没有班级信息
stu_class = pd.read_csv('班级.csv', encoding='utf-8')  # 仅含有班级和姓名的数据
dic = {}
score_index = 0  # 包含学生成绩的数据索引
class_index = -1  # 包含学生班级的数据索引
for name in stu_class['姓名']:
    class_index += 1
    for stu_score in data['姓名']:
        if score_index == len(data):
            score_index = 0
            break
        elif name != stu_score:
            score_index += 1
            continue
        elif name == stu_score:
            # 这里需要特别注意：班级跟成绩不是同一个index
            dic[name] = (stu_class['班级'][class_index][6:7], data['体测成绩'][score_index], data['学年平均学分绩点'][score_index], data['综合测评总分排名'][score_index], data['综合测评总分（百分制、精确到小数点后4位）'][score_index], data['学业成绩考核排名'][score_index])
            score_index = 0
            break
        else:
            pass
'''
说明：存储到csv文件中时，必须是数据框类型的数据才有to_csv的函数！且columns对应的数据必须是一个列表
'''
last_class = list()
last_pe = list()
last_gpa = list()
last_rank = list()
last_score = list()
last_gpa_rank = list()
for name in stu_class['姓名']:    # 要追加而不是覆盖
    try:
        last_class.append(dic[name][0])
        last_pe.append(dic[name][1])
        last_gpa.append(dic[name][2])
        last_rank.append(dic[name][3])
        last_score.append(dic[name][4])
        last_gpa_rank.append(dic[name][5])
    except KeyError:  # 部分名字没有对应的数据，那么try、except后，无数据的名字就会跳过了
        pass
 
last = pd.DataFrame()
last['姓名'] = list(dic.keys())
last['班级'] = last_class
last['体测'] = last_pe
last['绩点'] = last_gpa
last['绩点排名'] = last_gpa_rank
last['综测得分'] = last_score
last['综测排名'] = last_rank
 
result = pd.DataFrame(last, columns=['姓名', '班级', '体测', '绩点', '绩点排名', '综测得分', '综测排名'])
result.to_csv('最终文件.csv', index=False, encoding='gbk')