Python实现用networkx绘制MultiDiGraph
作者：EULE
这篇文章主要介绍了Python实现用networkx绘制MultiDiGraph方式,具有很好的参考价值,希望对大家有所帮助,如有错误或未考虑完全的地方,望不吝赐教
networkx绘制MultiDiGraph
美赛作图需要，想表现两个节点之间的双向关系，但是网上关于MultiDiGraph的内容很少，翻出去查了一下多向图的画法
记录一下
import matplotlib.pyplot as plt import networkx as nx G = nx.MultiDiGraph() #中间过程略 nx.draw(G,pos,connectionstyle='arc3, rad = 0.2',width=[float(v['weight']) for (r,c,v) in G.edges(data=True)]) #connectionstyle='arc3, rad = 0.2'arc控制双向，rad调线条弧度
最终效果↑
画图部分完整的代码
```python
G = nx.MultiDiGraph()
row=np.array(['D1','D2','D3','D4','D5','F1','F2','F3','M1','M6','M3','M4','M5','G1'])
G.add_nodes_from(['D1','D2','D3','D4','D5','F1','F2','F3','M1','M6','M3','M4','M5','G1'])
value=np.array(count)
for j in range(0,14):
for i in range(0,14):
if i!=j:
G.add_weighted_edges_from([(row[j],row[i],value[14*j+i])])#边的起点，终点，权重
else:
pass
node_sizes = [44,22,29,20,35,11,32,20,41,22,57,10,11,20]
node_sizesnew=[]
for i in node_sizes:
i=i*20
node_sizesnew.append(i)
pos={'D1':(37.29,77.42),'D2':(31.73,59.91),'D3':(40.47,27.53),'D4':(58.82,15.55),'D5':(46.29,89.65),'F1':(72,52),'F2':(61.64,45.73),'F3':(59.22,59.78),'G1':(11.64,49.73),'M1':(50.55,49.27),'M3':(46.56,56.18),'M4':(74.75,74.25),'M5':(58.25,46),'M6':(49.09,61.09)}
nx.draw_networkx_nodes(G,pos,node_size=node_sizesnew,alpha=0.4)
nx.draw_networkx_labels(G,pos,font_size=8,)
nx.draw(G,pos,edge_color='lightseagreen',alpha=0.5,connectionstyle='arc3, rad = 0.2',width=[float(v['weight']) for (r,c,v) in G.edges(data=True)])
edge_labels=dict([((u,v,),d['weight'])
for u,v,d in G.edges(data=True)])
plt.savefig("D:/MATCH52.png",dpi=200, bbox_inches='tight')
show()
print('finish')
总结
以上为个人经验，希望能给大家一个参考，也希望大家多多支持脚本之家。