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解决JdbcTemplate查询时报错Incorrect column count: expected 1, actual 17问题

2026-01-13 15:20:24 作者：五月天的尾巴

文章描述了在使用JdbcTemplate执行查询时遇到的`IncorrectResultSetColumnCountException`错误,原因是`queryForList`方法返回的是`List<Map<String, Object>>`类型,不能直接转换成对象,解决方法是将代码修改为适当的查询方式,以避免错误

一、报错内容

报错背景

使用JdbcTemplate执行查询时，报错了，代码及报错内容如下：

项目代码

String sql = "select * from user";
List<User> userList = jdbcTemplate.queryForList(sql,User.class);

报错信息

org.springframework.jdbc.IncorrectResultSetColumnCountException: Incorrect column count: expected 1, actual 5
   at org.springframework.jdbc.core.SingleColumnRowMapper.mapRow(SingleColumnRowMapper.java:92)
   at org.springframework.jdbc.core.RowMapperResultSetExtractor.extractData(RowMapperResultSetExtractor.java:93)
   at org.springframework.jdbc.core.RowMapperResultSetExtractor.extractData(RowMapperResultSetExtractor.java:60)
   at org.springframework.jdbc.core.JdbcTemplate$1QueryStatementCallback.doInStatement(JdbcTemplate.java:465)
   at org.springframework.jdbc.core.JdbcTemplate.execute(JdbcTemplate.java:407)
   at org.springframework.jdbc.core.JdbcTemplate.query(JdbcTemplate.java:477)
   at org.springframework.jdbc.core.JdbcTemplate.query(JdbcTemplate.java:487)
   at org.springframework.jdbc.core.JdbcTemplate.queryForObject(JdbcTemplate.java:497)
   at org.springframework.jdbc.core.JdbcTemplate.queryForObject(JdbcTemplate.java:503)
   at spring.mybatis.test.MyTest.test01(MyTest.java:25)
   at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
   at sun.reflect.NativeMethodAccessorImpl.invoke(Unknown Source)
   at sun.reflect.DelegatingMethodAccessorImpl.invoke(Unknown Source)
   at java.lang.reflect.Method.invoke(Unknown Source)
   at org.junit.runners.model.FrameworkMethod$1.runReflectiveCall(FrameworkMethod.java:50)
   at org.junit.internal.runners.model.ReflectiveCallable.run(ReflectiveCallable.java:12)
   at org.junit.runners.model.FrameworkMethod.invokeExplosively(FrameworkMethod.java:47)
   at org.junit.internal.runners.statements.InvokeMethod.evaluate(InvokeMethod.java:17)
   at org.junit.runners.ParentRunner.runLeaf(ParentRunner.java:325)
   at org.junit.runners.BlockJUnit4ClassRunner.runChild(BlockJUnit4ClassRunner.java:78)
   at org.junit.runners.BlockJUnit4ClassRunner.runChild(BlockJUnit4ClassRunner.java:57)
   at org.junit.runners.ParentRunner$3.run(ParentRunner.java:290)
   at org.junit.runners.ParentRunner$1.schedule(ParentRunner.java:71)
   at org.junit.runners.ParentRunner.runChildren(ParentRunner.java:288)
   at org.junit.runners.ParentRunner.access$000(ParentRunner.java:58)
   at org.junit.runners.ParentRunner$2.evaluate(ParentRunner.java:268)
   at org.junit.runners.ParentRunner.run(ParentRunner.java:363)
   at org.eclipse.jdt.internal.junit4.runner.JUnit4TestReference.run(JUnit4TestReference.java:86)
   at org.eclipse.jdt.internal.junit.runner.TestExecution.run(TestExecution.java:38)
   at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.runTests(RemoteTestRunner.java:459)
   at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.runTests(RemoteTestRunner.java:678)
   at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.run(RemoteTestRunner.java:382)
   at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.main(RemoteTestRunner.java:192)

报错原因

queryForList一般返回的是List<Map<>>类型，而不能直接转换成对象。

List<Map<String, Object>> list = jdbcTemplate.queryForList("select * from user");

二、解决方法

将代码修改为以下内容即可：

String sql = "select * from user";
List<User> userList = jdbcTemplate.query(sql,new BeanPropertyRowMapper<>(User.class));

三、总结

以上为个人经验，希望能给大家一个参考，也希望大家多多支持脚本之家。