Java前端实现发送date类型的参数给后端
作者：yololee_
@DateTimeFormat
第一次：Get方式传参-成功
这个时候是用的get请求方式，get是把参数数据队列加到提交表单的ACTION属性所指的URL中，值和表单内各个字段一一对应
/**
* http://localhost:8080/intoParam?date=2019-01-18 11:11:11
*/
@RequestMapping(value = "/intoParam",method = RequestMethod.GET)
@ResponseBody
public void intoParam(@DateTimeFormat(pattern = "yyyy-MM-dd HH:mm:ss") Date date){
System.out.println(date);//Fri Jan 18 08:00:00 CST 2019
}第二次：Post方式传参-失败
/**
* http://localhost:8080/intoParam
* 请求体
* {
* "date":"2019-01-18 11:11:11"
* }
*/
@RequestMapping(value = "/intoParam",method = RequestMethod.POST)
@ResponseBody
public void intoParam2(@RequestBody DateVo dateVo){
System.out.println(dateVo.getDate());//Fri Jan 18 08:00:00 CST 2019
}
@Data
@AllArgsConstructor
@NoArgsConstructor
public class DateVo {
@DateTimeFormat(pattern="yyyy-MM-dd HH:mm:ss")
private Date date;
}错误信息：
{
"timestamp": "2021-10-19T07:05:22.407+0000",
"status": 400,
"error": "Bad Request",
"message": "JSON parse error: Cannot deserialize value of type `java.util.Date` from String \"2019-01-18 11:11:11\": not a valid representation (error: Failed to parse Date value '2019-01-18 11:11:11': Cannot parse date \"2019-01-18 11:11:11\": while it seems to fit format 'yyyy-MM-dd'T'HH:mm:ss.SSSZ', parsing fails (leniency? null)); nested exception is com.fasterxml.jackson.databind.exc.InvalidFormatException: Cannot deserialize value of type `java.util.Date` from String \"2019-01-18 11:11:11\": not a valid representation (error: Failed to parse Date value '2019-01-18 11:11:11': Cannot parse date \"2019-01-18 11:11:11\": while it seems to fit format 'yyyy-MM-dd'T'HH:mm:ss.SSSZ', parsing fails (leniency? null))\n at [Source: (PushbackInputStream); line: 2, column: 12] (through reference chain: com.mye.hl20springbootdataparam.vo.DateVo[\"date\"])",
"path": "/intoParam"
}
第三次：post传参-成功
/**
* http://localhost:8080/intoParam
* 請求體是:
* {
* "date":"2019-01-18"
* }
*/
@RequestMapping(value = "/intoParam",method = RequestMethod.POST)
@ResponseBody
public void intoParam2(@RequestBody DateVo dateVo){
System.out.println(dateVo.getDate());//Fri Jan 18 08:00:00 CST 2019
SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd");
String format = sdf.format(dateVo.getDate());
System.out.println(format);//2019-01-18
}
@Data
@AllArgsConstructor
@NoArgsConstructor
public class DateVo {
@DateTimeFormat(pattern="yyyy-MM-dd")
private Date date;
}原因：
springboot默认采用jackson，而jackson只能识别以下几种日期格式
"yyyy-MM-dd'T'HH:mm:ss.SSSZ"； "yyyy-MM-dd'T'HH:mm:ss.SSS'Z'"； "yyyy-MM-dd"; "EEE, dd MMM yyyy HH:mm:ss zzz"; long类型的时间戳（毫秒时间戳）
解决方法：
- 采用long时间戳，如：1537191968000
- 在传参的对象上加上@JsonFormat注解并且指定时区
@JsonFormat(locale="zh", timezone="GMT+8", pattern="yyyy-MM-dd HH:mm:ss")
第四次：post传参-成功
/**
* http://localhost:8080/intoParam
* 請求體是:
* {
* "date":"2019-01-18 11:11:11"
* }
*/
@RequestMapping(value = "/intoParam",method = RequestMethod.POST)
@ResponseBody
public void intoParam2(@RequestBody DateVo dateVo){
System.out.println(dateVo.getDate());//Fri Jan 18 11:11:11 CST 2019
SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd");
String format = sdf.format(dateVo.getDate());
System.out.println(format);//2019-01-18 11:11:11
}
@Data
@AllArgsConstructor
@NoArgsConstructor
public class DateVo {
@DateTimeFormat(pattern="yyyy-MM-dd")
@JsonFormat(pattern="yyyy-MM-dd HH:mm:ss",timezone = "GMT+8")
private Date date;
}@jsonFormat
@JsonFormat(pattern=“yyyy-MM-dd”,timezone = “GMT+8”)
pattern:是你需要转换的时间日期的格式timezone：是时间设置为东八区，避免时间在转换中有误差@JsonFormat注解可以在属性的上方，同样可以在属性对应的get方法上，两种方式没有区别
/**
*http://localhost:8080/outParam
*/
@RequestMapping(value = "/outParam",method = RequestMethod.GET)
@ResponseBody
public DateVo intoParam2(){
return new DateVo(new Date());
}
@Data
@AllArgsConstructor
@NoArgsConstructor
public class DateVo {
// @DateTimeFormat(pattern="yyyy-MM-dd")
@JsonFormat(pattern="yyyy-MM-dd HH:mm:ss",timezone = "GMT+8")
private Date date;
}展示结果：
{
"date": "2021-10-19 15:44:51"
}总结
前端Content-Type 为application/json的请求时，我们使用@JsonFormat来进行转化，如果为表单，则应该使用@DateTimeFormat
以上为个人经验，希望能给大家一个参考，也希望大家多多支持脚本之家。