VBA数组去重(字典去重多种方法+数组去重2种方法)
作者:奔跑的犀牛先生
本文主要介绍了VBA数组去重(字典去重多种方法+数组去重2种方法),文中通过示例代码介绍的非常详细,对大家的学习或者工作具有一定的参考学习价值,需要的朋友们下面随着小编来一起学习学习吧
1 用字典的方法去重
- 方法1,用字典去重
- dict1(I) = ""
- 方法2,用字典去重 + 统计次数
- dict2(I) = dict2(I) + 1
- 方法3,用字典报重复,但没去重复
- If Not dict3.exists(I) Then
Sub test_dict1() Dim dict1 As Object Set dict1 = CreateObject("scripting.dictionary") Dim dict2 As Object Set dict2 = CreateObject("scripting.dictionary") Dim dict3 As Object Set dict3 = CreateObject("scripting.dictionary") arr1 = Range("b1:b10") '去重 For Each I In arr1 dict1(I) = "" Next For Each J In dict1.keys() Debug.Print J Next Debug.Print '去重 + 统计次数 For Each I In arr1 dict2(I) = dict2(I) + 1 Next For Each J In dict2.keys() Debug.Print J Next Debug.Print For Each K In dict2.items() Debug.Print K Next Debug.Print For Each I In arr1 If Not dict3.exists(I) Then dict3.Add I, "" Else Debug.Print "存在重复值" Exit Sub End If Next End Sub
2 用数组的方法去重
2.1 用数组循环的方法,去数组重复也可以
- 双循环
- 关键点1:双循环的目的是,循环拿1个数组,和另外一个循环的所有数做对比
- 关键点2:在外层赋值
- 关键点3:赋值的计数变量得独立,因为不知道有几个非重复数
Sub test_arr1() Dim arr2 arr1 = Array(1, 2, 3, 4, 5, 1, 2, 3, 1, 2, 1) ReDim arr2(UBound(arr1)) '在外面需要1次redim到位 For i = LBound(arr1) To UBound(arr1) For j = LBound(arr2) To UBound(arr2) If arr1(i) = arr2(j) Then GoTo line1 End If Next arr2(k) = arr1(i) k = k + 1 line1: Next For Each i In arr2 Debug.Print i Next End Sub
2.2 用循环数组方法,判断 每次内部循环,每次是否可以走一个完整循环
- 判断 每次内部循环,每次是否可以走一个完整循环
- 为了配合后面得index选择性的停在ubound+1上,否则都停在ubound+1上没法区分
- array的index指针停在ubound+1就证明内部循环完整走完没有exit for,证明无重复
Sub test_arr2() Dim arr2 arr1 = Array(1, 2, 3, 4, 5, 1, 2, 3, 1) ReDim arr2(LBound(arr1) To UBound(arr1)) '这样也没问题,一般有重复的列肯定更长 'ReDim arr2(LBound(arr1) To 99999) 这样也可以,就是故意搞1个极大数 K = 0 For I = LBound(arr1) To UBound(arr1) For J = LBound(arr2) To K If arr1(I) = arr2(J) Then Exit For '为了配合后面得index选择性的停在ubound+1上,否则都停在ubound+1上没法区分 End If Next If J = K + 1 Then 'array的index指针停在ubound+1就证明内部循环完整走完没有exit for,证明无重复 arr2(K) = arr1(I) K = K + 1 End If Next Debug.Print For Each m In arr2 Debug.Print m; Next Debug.Print End Sub
2.3用数组的方法查重复次数
2.3.1 用数组的方法查某个目标值的重复次数
Sub test001() '查某个值得重复次数 arr1 = Array(1, 2, 3, 4, 5, 1, 2, 3, 6, 7, 8, 9) target1 = 1 Debug.Print "arr1的最小index=" & LBound(arr1) Debug.Print "arr1的最大index=" & UBound(arr1) For I = LBound(arr1) To UBound(arr1) If arr1(I) = target1 Then Debug.Print target1 & "第" & m & "个" & "index=" & I End If Next End Sub
2.3.2 用数组+字典的方法查 每个元素重复次数
查所有元素的次数
Sub test002() '如果用循环方法查每个重复的值的重复次数 arr1 = Array(1, 2, 3, 4, 5, 1, 2, 3, 6, 7, 8, 9) Dim dict1 As Object Set dict1 = CreateObject("scripting.dictionary") Debug.Print "arr1的最小index=" & LBound(arr1) Debug.Print "arr1的最大index=" & UBound(arr1) arr2 = arr1 For I = LBound(arr1) To UBound(arr1) m = 1 For J = LBound(arr2) To UBound(arr2) If arr1(I) = arr2(J) Then dict1(arr1(I)) = m m = m + 1 End If Next Next For Each I In dict1.keys() Debug.Print I & "," & dict1(I) Next End Sub
只查部分元素的重复次数
Sub test002() '如果用循环方法查每个重复的值的重复次数 arr1 = Array(1, 2, 3, 4, 5, 1, 2, 3, 6, 7, 8, 9) Dim dict1 As Object Set dict1 = CreateObject("scripting.dictionary") Debug.Print "arr1的最小index=" & LBound(arr1) Debug.Print "arr1的最大index=" & UBound(arr1) arr2 = arr1 For I = LBound(arr1) To UBound(arr1) m = 1 For J = LBound(arr2) To UBound(arr2) If arr1(I) = arr2(J) Then If m >= 2 Then dict1(arr1(I)) = m End If m = m + 1 End If Next Next For Each I In dict1.keys() Debug.Print I & "," & dict1(I) Next End Sub
2.3.3 用纯数组的方法查呢?
- 不够好
- 因为还是得先 去重,否则就会如下很愚蠢的显示结果
Sub test002() '如果用循环方法查每个重复的值的重复次数 arr1 = Array(1, 2, 3, 4, 5, 1, 2, 3, 6, 7, 8, 9) Debug.Print "arr1的最小index=" & LBound(arr1) Debug.Print "arr1的最大index=" & UBound(arr1) arr2 = arr1 '每个元素必然至少重复1次 For I = LBound(arr1) To UBound(arr1) m = 0 For J = LBound(arr2) To UBound(arr2) If arr1(I) = arr2(J) Then m = m + 1 End If Next Debug.Print arr1(I) & "重复了" & m & "次" Next End Sub
其他方法
没看懂
https://cloud.tencent.com/developer/article/1468729
用collection方法的
https://www.cnblogs.com/sylar-liang/p/5563610.html
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