React 实现井字棋的示例代码
作者:卡卡舅舅
本文主要介绍了React 实现井字棋,文中通过示例代码介绍的非常详细,对大家的学习或者工作具有一定的参考学习价值,需要的朋友们下面随着小编来一起学习学习吧
一、简介
这篇文章会基于React 实现井字棋小游戏功能。
二、效果演示
三、技术实现
import {useEffect, useState} from "react"; export default (props) => { return <Board/> } const Board = () => { let initialState = [['', '', ''], ['', '', ''], ['', '', '']]; const [squares, setSquares] = useState(initialState); const [times, setTimes] = useState(0); useEffect(()=>{ // 判断每行是否相同 for (let i = 0; i < 3; i++) { if (squares[i][0] === squares[i][1] && squares[i][1] === squares[i][2] && squares[i][0] !== '') { alert(squares[i][0] + ' win'); setTimes(0) setSquares(initialState) return; } } // 判断每列是否相同 for (let i = 0; i < 3; i++) { if (squares[0][i] === squares[1][i] && squares[1][i] === squares[2][i] && squares[0][i] !== '') { alert(squares[0][i] + ' win') setTimes(0) setSquares(initialState) return; } } // 判断对角线是否相同 if (squares[0][0] === squares[1][1] && squares[1][1] === squares[2][2] && squares[0][0] !== '') { alert(squares[0][0] + ' win'); setTimes(0) setSquares(initialState) return; } if (squares[0][2] === squares[1][1] && squares[1][1] === squares[2][0] && squares[0][2] !== ''){ alert(squares[0][2] + ' win'); setTimes(0) setSquares(initialState) return; } },[times]) return <div style={{width:'130px', margin: '0 auto'}}> <table style={{borderCollapse: 'collapse'}}> {squares.map((row, rowIdx) => { return <tr key={rowIdx}> { row.map((col, colIdx) => { return <td key={rowIdx + '-' + colIdx} style={{border: '1px solid #000', width: '40px', height: '40px'}}> <div style={{width: '40px', height: '40px', textAlign: 'center', lineHeight:'40px'}} onClick={ () => { const newSquares = [...squares]; if (newSquares[rowIdx][colIdx] !== '') { return; } newSquares[rowIdx][colIdx] = times % 2 === 0 ? 'X' : 'O'; setSquares(newSquares); setTimes(times + 1); } }>{col}</div> </td> } ) } </tr> })} </table> </div> }
1.布局
基于table实现,3行,3列。
2.表格元素点击
更新cell内容,更新次数。
const newSquares = [...squares]; if (newSquares[rowIdx][colIdx] !== '') { return; } newSquares[rowIdx][colIdx] = times % 2 === 0 ? 'X' : 'O'; setSquares(newSquares); setTimes(times + 1);
3.判断游戏是否结束
判断每行,每列,斜线是否相等。
useEffect(()=>{ // 判断每行是否相同 for (let i = 0; i < 3; i++) { if (squares[i][0] === squares[i][1] && squares[i][1] === squares[i][2] && squares[i][0] !== '') { alert(squares[i][0] + ' win'); setTimes(0) setSquares(initialState) return; } } // 判断每列是否相同 for (let i = 0; i < 3; i++) { if (squares[0][i] === squares[1][i] && squares[1][i] === squares[2][i] && squares[0][i] !== '') { alert(squares[0][i] + ' win') setTimes(0) setSquares(initialState) return; } } // 判断对角线是否相同 if (squares[0][0] === squares[1][1] && squares[1][1] === squares[2][2] && squares[0][0] !== '') { alert(squares[0][0] + ' win'); setTimes(0) setSquares(initialState) return; } if (squares[0][2] === squares[1][1] && squares[1][1] === squares[2][0] && squares[0][2] !== ''){ alert(squares[0][2] + ' win'); setTimes(0) setSquares(initialState) return; } },[times])
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