python选择排序算法实例总结
作者：pythoner
这篇文章主要介绍了python选择排序算法,以三个实例以不同方法分析了Python实现选择排序的相关技巧,需要的朋友可以参考下
本文实例总结了python选择排序算法。分享给大家供大家参考。具体如下：
代码1：
def ssort(V):
#V is the list to be sorted
j = 0
#j is the "current" ordered position, starting with the first one in the list
while j != len(V):
#this is the replacing that ends when it reaches the end of the list
for i in range(j, len(V)):
#here it replaces the minor value that it finds with j position
if V[i] < V[j]:
#but it does it for every value minor than position j
V[j],V[i] = V[i],V[j]
j = j+1
#and here's the addiction that limits the verification to only the next values
return V
代码2：
def selection_sort(list):
l=list[:]
# create a copy of the list
sorted=[]
# this new list will hold the results
while len(l):
# while there are elements to sort...
lowest=l[0]
# create a variable to identify lowest
for x in l:
# and check every item in the list...
if x<lowest:
# to see if it might be lower.
lowest=x
sorted.append(lowest)
# add the lowest one to the new list
l.remove(lowest)
# and delete it from the old one
return sorted
代码3
a=input("Enter the length of the list :")
# too ask the user length of the list
l=[]
# take a emty list
for g in range (a):
# for append the values from user
b=input("Enter the element :")
# to ask the user to give list values
l.append(b)
# to append a values in a empty list l
print "The given eliments list is",l
for i in range (len(l)):
# to repeat the loop take length of l
index=i
# to store the values i in string index
num=l[i]
# to take first value in list and store in num
for j in range(i+1,len(l)):
# to find out the small value in a list read all values
if num>l[j]:
# to compare two values which store in num and list
index=j
# to store the small value of the loop j in index
num=l[j]
# to store small charecter are value in num
tem=l[i]
# to swap the list take the temparary list stor list vlaues
l[i]=l[index]
# to take first value as another
l[index]=tem
print "After the swping the list by selection sort is",l
希望本文所述对大家的Python程序设计有所帮助。