Python单链表的简单实现方法
投稿：shichen2014
这篇文章主要介绍了Python单链表的简单实现方法,包括定义所需的字段及具体实现代码的分析,需要的朋友可以参考下
本文实例讲述了Python单链表的简单实现方法，分享给大家供大家参考。具体方法如下：
通常来说，要定义一个单链表,首先定义链表元素:Element.它包含3个字段:
list:标识自己属于哪一个list
datum:改元素的value
next:下一个节点的位置
具体实现代码如下：
class LinkedList(object):
class Element(object):
def __init__(self,list,datum,next):
self._list = list
self._datum = datum
self._next = next
def getDatum(self):
return self._datum
datum = property(
fget = lambda self: self.getDatum())
def getNext(self):
return self._next
next = property(
fget = lambda self: self.getNext())
def __init__(self):
self._head = None
self._tail = None
def getHead(self):
return self._head
head = property(
fget = lambda self: self.getHead())
def prepend(self,item):
tmp = self.Element (self,item,self._head)
if self._head is None:
self._tail = tmp
self._head = tmp
def insert(self, pos, item):
i = 0
p = self._head
while p != None and i < pos -1:
p = p._next
i += 1
if p == None or i > pos-1:
return -1
tmp = self.Element(self, item, p._next)
p._next = tmp
return 1
def getItem(self, pos):
i = 0
p = self._head
while p != None and i < pos -1:
p = p._next
i += 1
if p == None or i > post-1:
return -1
return p._datum
def delete(self, pos):
i = 0
p = self._head
while p != None and i < pos -1:
p = p._next
i += 1
if p == None or i > post-1:
return -1
q = p._next
p._nex = q._next
datum = p._datum
return datum
def setItem(self, pos, item):
i = 0
p = self._head
while p != None and i < pos -1:
p = p._next
i += 1
if p == None or i > post-1:
return -1
p._datum = item
return 1
def find(self, pos, item):
i = 0
p = self._head
while p != None and i < pos -1:
if p._datum == item:
return 1
p = p._next
i += 1
return -1
def empty(self):
if self._head == None:
return 1
return 0
def size(self):
i = 0
p = self._head
while p != None and i < pos -1:
p = p._next
i += 1
return i
def clear(self):
self._head = None
self._tail = None
test = LinkedList()
test.prepend('test0')
print test.insert(1, 'test')
print test.head.datum
print test.head.next.datum
希望本文所述对大家的Python程序设计有所帮助。