JavaScript自定义DateDiff函数(兼容所有浏览器)
作者:
JavaScript自定义DateDiff函数兼容所有浏览器,DateDiff用来返回两个日期的时间间隔
复制代码 代码如下:
<script type="text/javascript">
function NewDate(str) {
str = str.split('-');
var date = new Date();
date.setUTCFullYear(str[0], str[1] - 1, str[2]);
date.setUTCHours(0, 0, 0, 0);
return date;
}
function TimeCom(dateValue) {
var newCom;
if (dateValue == "") {
newCom = new Date();
} else {
newCom = NewDate(dateValue);
}
this.year = newCom.getYear();
this.month = newCom.getMonth() + 1;
this.day = newCom.getDate();
this.hour = newCom.getHours();
this.minute = newCom.getMinutes();
this.second = newCom.getSeconds();
this.msecond = newCom.getMilliseconds();
this.week = newCom.getDay();
}
function DateDiff(interval, date1, date2) {
var TimeCom1 = new TimeCom(date1);
var TimeCom2 = new TimeCom(date2);
var result;
switch (String(interval).toLowerCase()) {
case "y":
case "year":
result = TimeCom1.year - TimeCom2.year;
break;
case "m":
case "month":
result = (TimeCom1.year - TimeCom2.year) * 12 + (TimeCom1.month - TimeCom2.month);
break;
case "d":
case "day":
result = Math.round((Date.UTC(TimeCom1.year, TimeCom1.month - 1, TimeCom1.day) - Date.UTC(TimeCom2.year, TimeCom2.month - 1, TimeCom2.day)) / (1000 * 60 * 60 * 24));
break;
case "h":
case "hour":
result = Math.round((Date.UTC(TimeCom1.year, TimeCom1.month - 1, TimeCom1.day, TimeCom1.hour) - Date.UTC(TimeCom2.year, TimeCom2.month - 1, TimeCom2.day, TimeCom2.hour)) / (1000 * 60 * 60));
break;
case "min":
case "minute":
result = Math.round((Date.UTC(TimeCom1.year, TimeCom1.month - 1, TimeCom1.day, TimeCom1.hour, TimeCom1.minute) - Date.UTC(TimeCom2.year, TimeCom2.month - 1, TimeCom2.day, TimeCom2.hour, TimeCom2.minute)) / (1000 * 60));
break;
case "s":
case "second":
result = Math.round((Date.UTC(TimeCom1.year, TimeCom1.month - 1, TimeCom1.day, TimeCom1.hour, TimeCom1.minute, TimeCom1.second) - Date.UTC(TimeCom2.year, TimeCom2.month - 1, TimeCom2.day, TimeCom2.hour, TimeCom2.minute, TimeCom2.second)) / 1000);
break;
case "ms":
case "msecond":
result = Date.UTC(TimeCom1.year, TimeCom1.month - 1, TimeCom1.day, TimeCom1.hour, TimeCom1.minute, TimeCom1.second, TimeCom1.msecond) - Date.UTC(TimeCom2.year, TimeCom2.month - 1, TimeCom2.day, TimeCom2.hour, TimeCom2.minute, TimeCom2.second, TimeCom1.msecond);
break;
case "w":
case "week":
result = Math.round((Date.UTC(TimeCom1.year, TimeCom1.month - 1, TimeCom1.day) - Date.UTC(TimeCom2.year, TimeCom2.month - 1, TimeCom2.day)) / (1000 * 60 * 60 * 24)) % 7;
break;
default:
result = "invalid";
}
return (result);
}
</script>