Java8中Stream流求最大值最小值的实现示例
作者：Archie_java
本文主要介绍了Java8中Stream流求最大值最小值的实现示例，文中通过示例代码介绍的非常详细，对大家的学习或者工作具有一定的参考学习价值，需要的朋友们下面随着小编来一起学习学习吧
一、BigDecimal 求最大值和最小值
1. stream().reduce()实现
List<BigDecimal> list = new ArrayList<>(Arrays.asList(new BigDecimal("1"), new BigDecimal("2")));
BigDecimal max = list.stream().reduce(list.get(0), BigDecimal::max);
BigDecimal min = list.stream().reduce(list.get(0), BigDecimal::min);
2. stream().max()或stream().min()实现
List<BigDecimal> list = new ArrayList<>(Arrays.asList(new BigDecimal("1"), new BigDecimal("2")));
BigDecimal max = list.stream().max(Comparator.comparing(x -> x)).orElse(null);
BigDecimal min = list.stream().min(Comparator.comparing(x -> x)).orElse(null);
二、Integer 求最大值和最小值
1. stream().reduce()实现
List<Integer> list = new ArrayList<>(Arrays.asList(1, 2)); Integer max = list.stream().reduce(list.get(0), Integer::max); Integer min = list.stream().reduce(list.get(0), Integer::min);
2. Collectors.summarizingInt()实现
List<Integer> list = new ArrayList<>(Arrays.asList(1, 2)); IntSummaryStatistics intSummaryStatistics = list.stream().collect(Collectors.summarizingInt(x -> x)); Integer max = intSummaryStatistics.getMax(); Integer min = intSummaryStatistics.getMin();
3. stream().max()或stream().min()实现
List<Integer> list = new ArrayList<>(Arrays.asList(1, 2)); Integer max = list.stream().max(Comparator.comparing(x -> x)).orElse(null); Integer min = list.stream().min(Comparator.comparing(x -> x)).orElse(null);
三、Long 求最大值和最小值
1. stream().reduce()实现
List<Long> list = new ArrayList<>(Arrays.asList(1L, 2L)); Long max = list.stream().reduce(list.get(0), Long::max); Long min = list.stream().reduce(list.get(0), Long::min);
2. Collectors.summarizingLong()实现
List<Long> list = new ArrayList<>(Arrays.asList(1L, 2L)); LongSummaryStatistics summaryStatistics = list.stream().collect(Collectors.summarizingLong(x -> x)); Long max = summaryStatistics.getMax(); Long min = summaryStatistics.getMin();
3. stream().max()或stream().min()实现
List<Long> list = new ArrayList<>(Arrays.asList(1L, 2L)); Long max = list.stream().max(Comparator.comparing(x -> x)).orElse(null); Long min = list.stream().min(Comparator.comparing(x -> x)).orElse(null);
四、Double 求最大值和最小值
1. stream().reduce()实现
List<Double> list = new ArrayList<>(Arrays.asList(1d, 2d)); Double max = list.stream().reduce(list.get(0), Double::max); Double min = list.stream().reduce(list.get(0), Double::min);
2. Collectors.summarizingLong()实现
List<Double> list = new ArrayList<>(Arrays.asList(1d, 2d)); DoubleSummaryStatistics summaryStatistics = list.stream().collect(Collectors.summarizingDouble(x -> x)); Double max = summaryStatistics.getMax(); Double min = summaryStatistics.getMin();
3. stream().max()或stream().min()实现
List<Double> list = new ArrayList<>(Arrays.asList(1d, 2d)); Double max = list.stream().max(Comparator.comparing(x -> x)).orElse(null); Double min = list.stream().min(Comparator.comparing(x -> x)).orElse(null);
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