python绘制玫瑰花情人节表白
作者：脑壳二
这篇文章主要介绍了python绘制玫瑰花，文章基于python的相关资料展开主题详细介绍，具有一定的参考价值，想情人节花式表白的小伙伴可以参考一下哟
一、玫瑰花绘制—深红色
import numpy as np
import matplotlib.pyplot as plt
from mpl_toolkits.mplot3d import Axes3D
fig = plt.figure()
ax = fig.gca(projection='3d')
[x, t] = np.meshgrid(np.array(range(25)) / 24.0, np.arange(0, 575.5, 0.5) / 575 * 30 * np.pi - 4*np.pi)
p = (np.pi / 2) * np.exp(-t / (8 * np.pi))
change = np.sin(20*t)/50
u = 1 - (1 - np.mod(3.3 * t, 2 * np.pi) / np.pi) ** 4 / 2 + change
y = 2 * (x ** 2 - x) ** 2 * np.sin(p)
r = u * (x * np.sin(p) + y * np.cos(p)) * 1.5
h = u * (x * np.cos(p) - y * np.sin(p))
c= plt.get_cmap('magma')
surf = ax.plot_surface(r * np.cos(t), r * np.sin(t), h, rstride=1, cstride=1,
cmap= c, linewidth=0, antialiased=True)
plt.show()二、玫瑰花绘制—五颜六色
import numpy as np
import matplotlib.pyplot as plt
from matplotlib import cm
from mpl_toolkits.mplot3d import Axes3D
fig = plt.figure()
ax = fig.gca(projection='3d')
[x, t] = np.meshgrid(np.array(range(25)) / 24.0, np.arange(0, 575.5, 0.5) / 575 * 17 * np.pi - 2 * np.pi)
p = (np.pi / 2) * np.exp(-t / (8 * np.pi))
u = 1 - (1 - np.mod(3.6 * t, 2 * np.pi) / np.pi) ** 4 / 2
y = 2 * (x ** 2 - x) ** 2 * np.sin(p)
r = u * (x * np.sin(p) + y * np.cos(p))
h = u * (x * np.cos(p) - y * np.sin(p))
c= cm.gist_rainbow_r
surf = ax.plot_surface(r * np.cos(t), r * np.sin(t), h, rstride=1, cstride=1,
cmap= c, linewidth=0, antialiased=True)
plt.show()三、玫瑰花绘制—粉红色
import numpy as np
import matplotlib.pyplot as plt
from matplotlib import cm
from mpl_toolkits.mplot3d import Axes3D
fig = plt.figure()
ax = fig.gca(projection='3d')
[x, t] = np.meshgrid(np.array(range(25)) / 24.0, np.arange(0, 575.5, 0.5) / 575 * 17 * np.pi - 2 * np.pi)
p = (np.pi / 2) * np.exp(-t / (8 * np.pi))
u = 1 - (1 - np.mod(3.6 * t, 2 * np.pi) / np.pi) ** 4 / 2
y = 2 * (x ** 2 - x) ** 2 * np.sin(p)
r = u * (x * np.sin(p) + y * np.cos(p))
h = u * (x * np.cos(p) - y * np.sin(p))
c= cm.get_cmap('spring_r')
surf = ax.plot_surface(r * np.cos(t), r * np.sin(t), h, rstride=1, cstride=1,
cmap= c, linewidth=0, antialiased=True)
plt.show()四、玫瑰花绘制—红色
# 省略了头文件，可以在之前的博客里看到
import numpy as np
import matplotlib.pyplot as plt
from mpl_toolkits.mplot3d import Axes3D
fig = plt.figure()
ax = fig.gca(projection='3d')
# 将相位向后移动了6*pi
[x, t] = np.meshgrid(np.array(range(25)) / 24.0, np.arange(0, 575.5, 0.5) / 575 * 20 * np.pi + 4*np.pi)
p = (np.pi / 2) * np.exp(-t / (8 * np.pi))
# 添加边缘扰动
change = np.sin(15*t)/150
# 将t的参数减少，使花瓣的角度变大
u = 1 - (1 - np.mod(3.3 * t, 2 * np.pi) / np.pi) ** 4 / 2 + change
y = 2 * (x ** 2 - x) ** 2 * np.sin(p)
r = u * (x * np.sin(p) + y * np.cos(p))
h = u * (x * np.cos(p) - y * np.sin(p))
c= plt.get_cmap('Reds')
surf = ax.plot_surface(r * np.cos(t), r * np.sin(t), h, rstride=1, cstride=1,
cmap= c, linewidth=0, antialiased=True)
plt.show()五、桃花绘制
import numpy as np
import matplotlib.pyplot as plt
from mpl_toolkits.mplot3d import Axes3D
fig = plt.figure()
ax = fig.gca(projection='3d')
[x, t] = np.meshgrid(np.array(range(25)) / 24.0, np.arange(0, 575.5, 0.5) / 575 * 6 * np.pi - 4*np.pi)
p = (np.pi / 2) * np.exp(-t / (8 * np.pi))
change = np.sin(10*t)/20
u = 1 - (1 - np.mod(5.2 * t, 2 * np.pi) / np.pi) ** 4 / 2 + change
y = 2 * (x ** 2 - x) ** 2 * np.sin(p)
r = u * (x * np.sin(p) + y * np.cos(p)) * 1.5
h = u * (x * np.cos(p) - y * np.sin(p))
c= plt.get_cmap('spring_r')
surf = ax.plot_surface(r * np.cos(t), r * np.sin(t), h, rstride=1, cstride=1,
cmap= c, linewidth=0, antialiased=True)
plt.show()到此这篇关于python绘制玫瑰花情人节表白的文章就介绍到这了,更多相关python绘制玫瑰花内容请搜索脚本之家以前的文章或继续浏览下面的相关文章希望大家以后多多支持脚本之家！