vue form表单post请求结合Servlet实现文件上传功能
作者：Megamind_HL
这篇文章主要介绍了vue form表单post请求结合Servlet实现文件上传功能，具有很好的参考价值，希望对大家有所帮助。一起跟随小编过来看看吧
前端测试页面代码：
<template>
<div>
<input type="file" name="file" @change="change($event)">
</div>
</template>
<script>
export default {
created(){
this.path = this.$route.query;
for (let i in this.path) {
this[i] = decodeURIComponent(this.path[i]);
}
},
methods:{
change(ev){
let file = ev.target.files[0];
let size = file.size;
let name = file.name;
if(size > 314572800){
this.$message.warning('上传文件不能超过300M');
return;
}
let formData = new FormData();
formData.append('file',file,name)
this.$axios.post('/JT3'+this.getddRecordDelete,formData,{
headers:{"Content-Type":"multipart/form-data"}
}).then(data=>{
console.log(data);
})
}
}
}
</script>
<style scoped>
</style>
后端servlet接收代码
package jt3.control.zygkh;
import java.io.File;
import java.io.FileOutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.util.List;
import javax.servlet.ServletException;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import org.apache.commons.fileupload.FileItem;
import org.apache.commons.fileupload.FileUploadException;
import org.apache.commons.fileupload.disk.DiskFileItemFactory;
import org.apache.commons.fileupload.servlet.ServletFileUpload;
import jtacc.filter.JTKit;
import jtacc.jtpub.DT;
@WebServlet(urlPatterns = "/upfile/file")
public class UploadServlet extends HttpServlet {
private static final long serialVersionUID = 1L;
protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
System.out.println(11);
this.doPost(request, response);
}
protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
String uri="/u/file/"+DT.getFormatDate("yyyyMMdd")+"/"; //定义路径
String tmpPath=JTKit.getBaseDIR()+uri;//此处为个人项目路径，根据需求定义路径
DiskFileItemFactory factory = new DiskFileItemFactory();
factory.setRepository(new File(tmpPath));//临时文件存储路径
ServletFileUpload fileUpload = new ServletFileUpload(factory);//核心操作对象
fileUpload.setHeaderEncoding("utf-8");//防乱码
try {
//此处如果要实时强行转换则需要下载jar包（commons-fileupload-1.3.3.jar）
List<FileItem> list = fileUpload.parseRequest(request);
for (FileItem fileItem : list) {
InputStream in = fileItem.getInputStream();
String filename = fileItem.getName();
if (fileItem != null) {
System.out.println(filename);
int len = 0;
byte[] array = new byte[1024];
FileOutputStream fos = new FileOutputStream(tmpPath+filename);
while((len = in.read(array))!=-1){//表示每次最多读1024个字节
fos.write(array,0,len);
fos.flush();
}
fos.close();
in.close();
fileItem.delete();
response.setCharacterEncoding("UTF-8");
String realPath = uri+filename;
response.getWriter().append(realPath);
}
}
} catch (FileUploadException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
}
测试结果
补充：Servlet获取表单提交过来的数据
在Servlet的doPost方法：
protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
}
中获取表单数据，首先，为了防止出现中文乱码问题，需要给request设置编码为“UTF-8”：
request.setCharacterEncoding("utf-8");
获取单个字符串的方式：
<pre style="font-family: 宋体; font-size: 12pt; background-color: rgb(255, 255, 255);"><span style="font-size:18px; font-family: Arial, Helvetica, sans-serif; background-color: rgb(240, 240, 240);">String username = request.getParameter("username");</span>
获取字符串数组的方式：
String[] favorites = request.getParameterValues("favorite");
以上为个人经验，希望能给大家一个参考，也希望大家多多支持脚本之家。如有错误或未考虑完全的地方，望不吝赐教。