Python 解析XML文件
作者:
google一篇关于Python解析XML文件的博文不过XML文件出错,整理如下。
Python文件:
#parsexml.py
#本例子参考自python联机文档,做了适当改动和添加
import xml.parsers.expat
#控制打印缩进
level = 0
#获取某节点名称及属性值集合
def start_element(name, attrs):
global level
print ' '*level, 'Start element:', name, attrs
level = level + 1
#获取某节点结束名称
def end_element(name):
global level
level = level - 1
print ' '*level, 'End element:', name
#获取某节点中间的值
def char_data(data):
if(data == '\n'):
return
if(data.isspace()):
return
global level
print ' '*level, 'Character data:', data
p = xml.parsers.expat.ParserCreate()
p.StartElementHandler = start_element
p.EndElementHandler = end_element
p.CharacterDataHandler = char_data
p.returns_unicode = False
f = file('sample.xml')
p.ParseFile(f)
f.close()
XML文件(sample.xml):
<contacts id="bluecrystal">
<item name="keen" fff="ddd">
<telephone type="phone">222222222</telephone>
<telephone type="mobile">134567890</telephone>
</item>
<item name="bcm">
<telephone type="phone">11111111</telephone>
<telephone type="mobile">15909878909</telephone>
</item>
</contacts>
复制代码 代码如下:
#parsexml.py
#本例子参考自python联机文档,做了适当改动和添加
import xml.parsers.expat
#控制打印缩进
level = 0
#获取某节点名称及属性值集合
def start_element(name, attrs):
global level
print ' '*level, 'Start element:', name, attrs
level = level + 1
#获取某节点结束名称
def end_element(name):
global level
level = level - 1
print ' '*level, 'End element:', name
#获取某节点中间的值
def char_data(data):
if(data == '\n'):
return
if(data.isspace()):
return
global level
print ' '*level, 'Character data:', data
p = xml.parsers.expat.ParserCreate()
p.StartElementHandler = start_element
p.EndElementHandler = end_element
p.CharacterDataHandler = char_data
p.returns_unicode = False
f = file('sample.xml')
p.ParseFile(f)
f.close()
XML文件(sample.xml):
复制代码 代码如下:
<contacts id="bluecrystal">
<item name="keen" fff="ddd">
<telephone type="phone">222222222</telephone>
<telephone type="mobile">134567890</telephone>
</item>
<item name="bcm">
<telephone type="phone">11111111</telephone>
<telephone type="mobile">15909878909</telephone>
</item>
</contacts>