python 二维数组90度旋转的方法
作者：零_锋
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如下所示：
#!/usr/bin/env python #-*- coding: utf-8 -*- """ [0, 1, 2, 3] [0, 1, 2, 3] [0, 1, 2, 3] [0, 1, 2, 3] 2维数组顺时针90度旋转后结果如下 [0, 0, 0, 0] [1, 1, 1, 1] [2, 2, 2, 2] [3, 3, 3, 3] [0][1] <==> [1][0] [0][2] <==> [2][0] [0][3] <==> [3][0] [1][2] <==> [2][1] [1][3] <==> [3][1] [2][3] <==> [3][2] """ data=[[i for i in range(4)] for raw in range(4)] for ele in data: print ele a=len(data) for i in range(a):#外层循环 for j in range(i+1,len(data[i])): #内层循环 #交换数据 temp=data[i][j] data[i][j]=data[j][i] data[j][i]=temp for ele in data: print ele
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