angularJS1 url中携带参数的获取方法
作者：xiejunna
今天小编就为大家分享一篇angularJS1 url中携带参数的获取方法，具有很好的参考价值，希望对大家有所帮助。一起跟随小编过来看看吧
index.html 从此界面跳转到a.html界面
<!doctype html>
<html>
<head>
<meta charset="utf-8">
<title>form demo</title>
<meta name="viewport" content="width=device-width, minimum-scale=1.0, maximum-scale=1.0, user-scalable=0" />
<script src="js/angular.min.1.6.0.js"></script>
</head>
<body ng-app="app" ng-controller="myctrl">
<button ng-click="jump()" >点击跳转下一页</button>
<br /><br />
<a ng-href="a.html?name=xie&age=25&gender=nv" rel="external nofollow" >点击跳转下一页</a>
</div>
</body>
<script>
var app = angular.module('app', []);
app.controller('myctrl', function($scope, $window) {
$scope.jump = function() {
$window.location.href = 'a.html?name=xie&age=25&gender=nv';
}
});
</script>
</html>
a.html 跳转到的目标界面，在此界面获取url携带的参数：
<!DOCTYPE html>
<html>
<head>
<meta charset="UTF-8">
<meta name="viewport" content="width=device-width, minimum-scale=1.0, maximum-scale=1.0, user-scalable=0" />
<script src="js/angular.min.1.6.0.js"></script>
<title></title>
</head>
<body ng-app="myapp" ng-controller="myctrl" >
<p>a.html</p>
</body>
<script>
//Url="http://168.33.222.69:8020/angularjs_demo/a.html?name=xie&age=25&gender=nv";
var app=angular.module("myapp",[]);
app.config(['$locationProvider', function($locationProvider) {
// $locationProvider.html5Mode(true);
$locationProvider.html5Mode({
enabled: true,
requireBase: false
});
}]);
app.controller('myctrl', function($scope, $location) {
console.log($location.search().name);
console.log($location.search().age);
console.log($location.search().gender);
});
//打印结果：
//[Web浏览器] "xie"
//[Web浏览器] "25"
//[Web浏览器] "nv"
</script>
</html>
以上这篇angularJS1 url中携带参数的获取方法就是小编分享给大家的全部内容了，希望能给大家一个参考，也希望大家多多支持脚本之家。