jsp页面中获取servlet请求中的参数的办法详解
投稿：wdc
在JAVA WEB应用中，如何获取servlet请求中的参数,本文讲解了jsp页面中获取servlet请求中的参数的办法
在JAVA WEB应用中，如何获取servlet请求中的参数，并传递给跳转的JSP页面？例如访问http://localhost:8088/bbs?id=1
当执行这个bbs servlet时，将url参数id的值传递给bbs.jsp页面？
1.首先要配置web.xml，见下面的配置：
<servlet> <servlet-name>bbs</servlet-name> <servlet-class> org.openjweb.core.servlet.BBSServlet </servlet-class> </servlet> <servlet-mapping> <servlet-name>bbs</servlet-name> <url-pattern>/bbs</url-pattern> </servlet-mapping>
2.编写servlet类：
package org.openjweb.core.servlet;
import java.io.IOException;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
public class BBSServlet extends HttpServlet
{
private static final long serialVersionUID = 1L;
public BBSServlet()
{
super();
// TODO Auto-generated constructor stub
}
protected void doGet(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException
{
//http://bbs.csdn.net/topics/90438353
request.setCharacterEncoding("UTF-8"); //设置编码
String id = request.getParameter("id");
request.setAttribute("id", id);
request.getRequestDispatcher("/bbs.jsp").forward(request, response);
}
protected void doPost(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException
{
doGet(request, response);
}
}
在应用根目录创建bbs.jsp文件，内容为：
<%@ page contentType="text/html;charset=UTF-8"%>
<%
out.println(request.getAttribute("id"));
%>
注意很多人传递参数不成功是因为是在doGet方法中调用doPost,这里doGet方法不要调用doPost.