Python基于分水岭算法解决走迷宫游戏示例
作者:白交_Robin
这篇文章主要介绍了Python基于分水岭算法解决走迷宫游戏,结合具体实例形式分析了分水岭算法解决迷宫问题的相关步骤与操作技巧,需要的朋友可以参考下
本文实例讲述了Python基于分水岭算法解决走迷宫游戏。分享给大家供大家参考,具体如下:
#Solving maze with morphological transformation """ usage:Solving maze with morphological transformation needed module:cv2/numpy/sys ref: 1.http://www.mazegenerator.net/ 2.http://blog.leanote.com/post/leeyoung/539a629aab35bc44e2000000 @author:Robin Chen """ import cv2 import numpy as np import sys def SolvingMaze(image): #load an image try: img = cv2.imread(image) except Exception,e: print 'Error:can not open the image!' sys.exit() #show image #cv2.namedWindow('image', cv2.WINDOW_NORMAL) cv2.imshow('maze_image',img) #convert to gray gray_image = cv2.cvtColor(img, cv2.COLOR_BGR2GRAY) #show gray image #cv2.imshow('gray_image',gray_image) #convert to binary image retval,binary_image = cv2.threshold(gray_image, 10,255, cv2.THRESH_BINARY_INV) #cv2.imshow('binary_image',binary_image) contours,hierarchy = cv2.findContours(binary_image, cv2.RETR_EXTERNAL, cv2.CHAIN_APPROX_NONE) if len(contours) != 2: sys.exit("This is not a 'perfect maze' with just 2 walls!") h, w, d = img.shape #The first wall path = np.zeros((h,w),dtype = np.uint8)#cv2.CV_8UC1 cv2.drawContours(path, contours, 0, (255,255,255),-1)#cv2.FILLED #cv2.imshow('The first wall',path) #Dilate the wall by a few pixels kernel = np.ones((19, 19), dtype = np.uint8) path = cv2.dilate(path, kernel) #cv2.imshow('Dilate the wall by a few pixels',path) #Erode by the same amount of pixels path_erode = cv2.erode(path, kernel); #cv2.imshow('Erode by the same amount of pixels',path_erode) #absdiff path = cv2.absdiff(path, path_erode); #cv2.imshow('absdiff',path) #solution channels = cv2.split(img); channels[0] &= ~path; channels[1] &= ~path; channels[2] |= path; dst = cv2.merge(channels); cv2.imshow("solution", dst); #waiting for any key to close windows cv2.waitKey(0) cv2.destroyAllWindows() if __name__ == '__main__': image = sys.argv[-1] SolvingMaze(image)
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