C语言实现直角坐标转换为极坐标的方法
作者：e421083458
这篇文章主要介绍了C语言实现直角坐标转换为极坐标的方法,涉及C语言进行三角函数与数值运算相关操作技巧,需要的朋友可以参考下
本文实例讲述了C语言实现直角坐标转换为极坐标的方法。分享给大家供大家参考，具体如下：
#include<stdio.h>
#include<math.h>
struct complex_s{
double x,y;
};
double real_part(struct complex_s z){
return z.x;
}
double img_part(struct complex_s z){
return z.y;
}
double magnitude(struct complex_s z){
return sqrt(z.x*z.x + z.y*z.y);
}
double angle(struct complex_s z){
return atan2(z.y, z.x);
}
struct complex_s make_from_real_img(double x, double y){
struct complex_s z;
z.x = x;
z.y = y;
return z;
}
struct complex_s make_from_mag_ang(double r, double A){
struct complex_s z;
z.x = r * cos(A);
z.y = r * sin(A);
return z;
}
struct complex_s add_complex(struct complex_s z1,struct complex_s z2){
return make_from_real_img(real_part(z1)+real_part(z2),
img_part(z1) + img_part(z2));
}
struct complex_s sub_complex(struct complex_s z1,struct complex_s z2){
return make_from_real_img(real_part(z1)-real_part(z2),
img_part(z1) - img_part(z2));
}
struct complex_s mul_complex(struct complex_s z1,struct complex_s z2){
return make_from_mag_ang(real_part(z1)*real_part(z2),
img_part(z1) + img_part(z2));
}
struct complex_s div_complex(struct complex_s z1,struct complex_s z2){
return make_from_mag_ang(real_part(z1)/real_part(z2),
img_part(z1) + img_part(z2));
}
int main(void){
struct complex_s z1 = {3.0,4.0};
struct complex_s z2= {2.0,5.0};
struct complex_s x;
x = add_complex(z1,z2);
printf("x={%f,%f}",x.x,x.y);
return 0;
}
结果：
[root@localhost struct]# ./jizuobiao.out
x={5.000000,9.000000}
希望本文所述对大家C语言程序设计有所帮助。